In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

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In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)

A 80%

B70%

C75%

D 62%

Nithin ? undefined

Correct answer is: 80%
Explanation:

Water in 60 gm mixture= \(60 \times \frac{75}{100}\) = 45 gm. and Milk = 15 gm.

After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.

So % of water = \(100 \times \frac{60}{75}\) = 80%

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Ratio of Rams and Komars age is 3 : 5 respectively. Ratio of Komal's and Pooja's age is 2 : 3 respectively. If Rani is two-fifth of Pooja's age. what is Rani's age?

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Ratio of Rams and Komars age is 3 : 5 respectively. Ratio of Komal's and Pooja's age is 2 : 3 respectively. If Rani is two-fifth of Pooja's age. what is Rani's age?

A10 years

B15 years

C24 years

DCannot be determined

Nithin ? Aug 14 '2022 at 16:38

Correct answer is: Cannot be determined

Explanation:

Rani : Komal = \(3 : 5 = 6 : 10\)

Komal : Pooja = \( 2 : 3 = 10 : 15\)

Therefore, Rani : Kornal : Pooja = \(6 : 10 : 15\)

We have insufficient data to solve this question.

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The average weight of a group of 53 girls was calculated as 58 kgs. It was later discovered that the weight of one of the girls was read as 65 kgs., whereas her actual weight was 45 kgs. What is the actual average weight of the group of 53 girls ?(rounded off to two digits after decimal)

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The average weight of a group of 53 girls was calculated as 58 kgs. It was later discovered that the weight of one of the girls was read as 65 kgs., whereas her actual weight was 45 kgs. What is the actual average weight of the group of 53 girls ?(rounded off to two digits after decimal)

A58.62 kgs

B58.37 kgs

C57.37 kgs

D57.62 kgs

Nithin K ? Apr 20 '2017 at 20:43

Answer is 57.62 kgs

Explanation

Actual weight of 53 girls= 53 × 58 + 45 - 65

= 3074 + 45 - 65

= 3054 kg.

Required actual average weight= \(\frac{3054}{53}\)= 57.62 kg

 

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The sum of five numbers is 290. The average of the first two numbers is 48.5 and the average of last two numbers is 53.5. What is the third number ?

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The sum of five numbers is 290. The average of the first two numbers is 48.5 and the average of last two numbers is 53.5. What is the third number ?

A72

B84

C86

D108

Nithin K ? Apr 19 '2017 at 23:25

Answer is 86

Explanation

Third number = 290 - 2 × 48.5 - 2 × 53.5

= 290 - 97 - 107

= 86

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