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Friday, March 28, 2025

A sum of Rs. 15000 is invested at 10% compound interest for 2 years. Find the amount after 2 years.

March 28, 2025 |

Compound Interest, General Aptitude, RRB NTPC Exam 27 Jan 2021, Solved

A sum of Rs. 15000 is invested at 10% compound interest for 2 years. Find the amount after 2 years.

ARs. 15510

BRs. 18150

CRs. 19820

DRs. 18754

Akhilesh Apr 1 '25 at 20:45

correct answer is: option b (b)[Rs. 18150]
Explanation: The formula for compound interest is $A = P(1 + \frac{r}{100})^n$ , where A is the amount after n years, P is the principal amount, r is the rate of interest, and n is the number of years.
In this case, P = Rs. 15000, r = 10%, and n = 2 years.
So, $A = 15000(1 + \frac{10}{100})^2 = 15000(1 + 0.1)^2 = 15000(1.1)^2 = 15000 * 1.21 = 18150$ . Therefore, the amount after 2 years is Rs. 18150

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Find the amount after 3 years if the rate of interest is 15% per annum and principal is Rs. 24,000.

March 28, 2025 |

Compound Interest, General Aptitude, RRB NTPC Exam 27 Jan 2021, Solved

Find the amount after 3 years if the rate of interest is 15% per annum and principal is Rs. 24,000.

ARs. 30,900

BRs. 32,700

CRs. 36,500

DRs. 34,800

Akhilesh Mar 31 '25 at 22:43

correct answer is: Rs. 34,800
Explanation: To find the amount after 3 years with a principal of Rs. 24,000 and an annual interest rate of 15%, we can use the simple interest formula: $A = P + PRT$ Where:
- $P = 24,000$ (principal amount)
- $R = 15\% = 0.15$ (annual interest rate)
- $T = 3$ years Plugging in the values: $A = 24,000 + (24,000 \times 0.15 \times 3)$ $A = 24,000 + 10,800$ $A = 34,800$ Thus, the amount after 3 years is Rs. 34,800.

OPTION a (Rs. 30,900): Too low; doesn't match the calculated amount.

OPTION b (Rs. 32,700): Still too low; doesn't match the calculated amount.

OPTION c (Rs. 36,500): Too high; likely assumes compound interest, which wasn't specified.

OPTION d (Rs. 34,800): Correct; matches the calculated amount using simple interest.

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Saturday, December 14, 2019

A builder borrows Rs.2550 to be paid back with compound interest at the rate of4% per annum by the end of 2 yr in two equal yearly installments. How muchwill each installment be?

December 14, 2019 |

Compound Interest, General Aptitude, RRB GG Exam (Bhopal) 2009, Solved

A builder borrows Rs.2550 to be paid back with compound interest at the rate of 4% per annum by the end of 2 yr in two equal yearly installments. How much will each installment be?

ARs.1352

BRs.1377

CRs.1275

DRs.1283

prakash Dec 23 '2019 at 10:32

Correct answer is: Rs.1352

Explanation:

Amount = Rs 2550

Rate = 4% per annum

Time = 2 years

Applying the formula

$P= \frac{X}{\Big(1+\frac{r}{100}\Big)^n}+ …………………….\frac{X}{\Big(1+\frac{r}{100}\Big)}$

Here we have two equal installments, so

$P= \frac{X}{\Big(1+\frac{r}{100}\Big)^2} + \frac{X}{\Big(1+\frac{r}{100}\Big)}$

$\implies 2550= \frac{X}{\Big(1+\frac{4}{100}\Big)^2} + \frac{X}{\Big(1+\frac{4}{100}\Big)}$

$\implies X = \text{ Rs 1352}$

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Wednesday, December 26, 2018

What will be the difference between SI and CI on a sum of Rs.15,000 for twoyears at the same rate of interest of 121−2% per annum?

December 26, 2018 |

Compound Interest, General Aptitude, RRB TC CC Exam (Mumbai) 2006, Simple Interest, Solved

What will be the difference between SI and CI on a sum of Rs.15,000 for twoyears at the same rate of interest of 121−2% per annum?

ARs.234.375

BRs.230.550

CRs.250.129

DRs.324.357

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Tuesday, December 25, 2018

If CP is Rs.2,516 and SP is Rs.2,272, then percentage loss is

December 25, 2018 |

Compound Interest, General Aptitude, Percentage, RRB TC CC Exam (Mumbai) 2006, Simple Interest, Solved

If CP is Rs.2,516 and SP is Rs.2,272, then percentage loss is

A0.0871

B0.0743

C0.0969

D0.1028

Akilesh Kharvi Nov 6 '2016 at 11:44

Answer is : 0.0969

Loss = Rs (2516-2272)
Loss = Rs. 244
so, Percentage of loss is
= $244\over2516$ => 0.0969

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