A money - lender borrows money at 4% per annum and pays the

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A money - lender borrows money at 4% per annum and pays the interest at the end of the year. He lends it at 6% per annum compound interest compounded halfy early and receives the interest at the end of the year. In this way, he gains Rs.104.50 a year. The amount of money he borrows, is

ARs.6,000

BRs.5,500

CRs.5,000

DRs.4,500

Nithin K ? Nov 23 '2016 at 21:26

Answer is : Rs.5,000

Let he borrowed Rs x

borrows money at 4% per annum and pays the interest at the end of the year

Amount he has to return = \(\frac{104x}{100}\)

Amount he will get = \(\big(1+\frac{3}{100}\big)^2 = \frac{10609}{10000}x\)

His gain = \(\frac{10609}{10000}x = \frac{104}{100}x = 104.50\)

\(x\big(\frac{10609}{10000}-\frac{104}{100}\big)=104.50\)

\(x\big(\frac{10609}{10000}-\frac{10400}{10000}\big) = 104.50\)

\(x\big(\frac{10609-10400}{10000}\big)=104.50\)

\(x\big(\frac{209}{10000}\big)=104.50\)

\(x=\frac{104.50 * 10000}{209}\)

\(x = \text{Rs }5000\)

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If the compound interest on a sum for 2 yr at 12.5% per anum

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If the compound interest on a sum for 2 yr at 12.5% per annum is Rs.510, the simple interest on the same sum at the same rate for the same period of time is

ARs.400

BRs.480

CRs.450

DRs.460

Md Hasnain Reza ? Mar 23 '2018 at 17:5

Correct answer is: Rs.480
Explanation: Let's recalculate the answer. We have: - Compound Interest (CI) = Rs. 510 - Time period (T) = 2 years - Rate of interest (R) = 12.5% To find the principal amount (P), we'll use the formula for compound interest: \[CI = P \left(1 + \frac{R}{100}\right)^T - P\] Substituting the given values: \[510 = P \left(1 + \frac{12.5}{100}\right)^2 - P\] Let's first calculate \(\left(1 + \frac{12.5}{100}\right)^2\): \[\left(1 + \frac{12.5}{100}\right)^2 = \left(1.125\right)^2 = 1.265625\] So, the equation becomes: \[510 = P \times 1.265625 - P\] \[510 = 1.265625P - P\] \[510 = 0.265625P\] Now, divide both sides by \(0.265625\) to find \(P\): \[P = \frac{510}{0.265625}\] \[P ≈ 1919.047619\] Now that we have the principal amount (\(P\)), let's calculate the simple interest (SI) using the formula: \[SI = P \times R \times T\] Substituting the values of \(P\), \(R\), and \(T\): \[SI = 1919.047619 \times \frac{12.5}{100} \times 2\] \[SI ≈ 479.7619\] Rounding to the nearest rupee, the simple interest is approximately Rs. 480. Therefore, the correct answer is option B. Rs. 480. Thank you for your patience, and I apologize for any confusion caused.

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What is the compound interest accrued on an amount of Rs.120 t

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What is the compound interest accrued on an amount of Rs.12000 at the rate of 9% per annum. At the end of 2 yr?

ARs.2545

BRs.2257.2

CRs.2986

DRs.2775.4

Nithin K ? Dec 4 '2016 at 10:55

Answer: Rs.2257.2

Explanation:

Formula:  \(C.I. = P \Big[ 1 + \frac{R}{100} \Big]^T -P\)

Where, P = 12000 , R =9, T =2

\(C.I. = 12000  \Big[ 1 + \frac{9}{100} \Big]^2 -12000 \)

= 12000 [1.1881] -12000

= 14257.2 - 12000

= Rs.2257.2

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Ms. Anisha deposits an amount of Rs.35000 to obtain a simpl

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Ms. Anisha deposits an amount of Rs.35000 to obtain a simple interest at the rate of 15% per annum for 4 yr. What total amount will Ms. Anisha get at the end of 4 yr?

ARs.56000

BRs.60500

CRs.52000

DRs.48500

Nithin K ? Dec 4 '2016 at 10:33

Answer: Rs.56000

Explanation:

Formula: \(Amount = P \Big\{a + \frac{TR}{100} \Big\}\)

\(Amount = 35000 \Big\{1+  \frac{4 \times 15}{100} \Big\} = 56000.\)

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