The average marks of subject Maths and English is

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The average marks of a student in Maths and English is 90. If the student scored 85 marks in Maths, what were their marks in English?

A90

B120

C110

D115

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HCF of 910, 325, 615, 125 is:

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HCF of 910, 325, 615, 125 is:

A5

B1150

C350

D150

Akhilesh ? Apr 3 '25 at 21:40

correct answer is: 5
Explanation: The HCF of 910, 325, 615, and 125 is determined by identifying the highest common prime factor among all numbers. The prime factorizations are:
- 910: 2 × 5 × 7 × 13
- 325: 5² × 13
- 615: 3 × 5 × 41
- 125: 5³ The only common prime factor is 5. Therefore, the HCF is 5. However, since 5 is not listed among the provided options (50, 1150, 350, 150), there might be an error in the question or the options provided.

• OPTION a: 50
  - 50 is not a factor of 325 (325 ÷ 50 = 6.5, not an integer).
• OPTION b: 1150
  - 1150 is greater than some of the numbers, so it cannot be their HCF.
• OPTION c: 350
  - 350 is not a factor of 325 (325 ÷ 350 = 0.928, not an integer).
• OPTION d: 150
  - 150 is not a factor of 325 (325 ÷ 150 ≈ 2.166, not an integer).

 

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Ratio of two number is 5: 6 and their HCF is 6. LCM of these two numbers is:

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Ratio of two number is 5: 6 and their HCF is 6. LCM of these two numbers is:

A150

B180

C90

D120

Akhilesh ? Apr 3 '25 at 21:26

correct answer is: 180
Explanation: The ratio of the two numbers is 5:6, so let the numbers be 5k and 6k.

The HCF of these numbers is k. Given that the HCF is 6, we find k=6.

Thus, the numbers are 30 and 36.

Using the formula $\text{LCM(a,b)} = \frac{(a \times b)}{\text{HCF(a,b)}}$,

the LCM is $\frac{(30\times36)}{6}$ = 180.

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A man was travelling half of the total distance at a speed of 30 km/h and the rest distance at the speed of 50 km/h. What was the average speed of the man on his whole journey?

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A man was travelling half of the total distance at a speed of 30 km/h and the rest distance at the speed of 50 km/h. What was the average speed of the man on his whole journey?

A40 km/hr

B37.5 km/hr

C42.5 km/hr

D35 km/hr

Akhilesh ? Apr 3 '25 at 21:17

correct answer is: 37.5 km/hr
Explanation: To find the average speed for the entire journey,

we use the formula for average speed when covering equal distances:

$$\text{Average Speed} = \frac{2 \times v_1 \times v_2}{v_1 + v_2}$$ where $v_1 = 30$ km/h and $v_2 = 50$ km/h.

Plugging in the values:

$$\text{Average Speed} = \frac{2 \times 30 \times 50}{30 + 50} = \frac{3000}{80} = 37.5 \text{ km/h}$$

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What is the difference between largest and smallest number of six digits?

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What is the difference between largest and smallest number of six digits?

A90000

B899999

C89999

D889999

Akhilesh ? Apr 3 '25 at 21:28

correct answer is: option b (899999)
Explanation: The largest six-digit number is 999999, and the smallest six-digit number is 100000. The difference between them is 999999 - 100000 = 899999.

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