Which of the following is always found In free stable in nature ?
Which of the following is always found In free stable in nature ?
Which of the following is always found In free stable in nature ?
Nithin K ? Apr 21 '2018 at 20:6
Correct Answer: A [Gold]
Explanation:
Gold is chemically very less active and hence found in free state in nature.
Which of the following is acidic In nature ?
Nithin K ? Apr 21 '2018 at 18:39
Correct Answer: D [Vlnegar]
Explanation:
Vinegar is chemically : 4-8% Acetic Acid CH3COOH and hence it is acidic in nature.
The logarithm of 0.0625 to the 2 is
Nithin K ? Apr 21 '2018 at 18:16
Correct Answer: A [-4]
Explanation:
\(log_{2}0.0625=log_{2}\Big(\frac{625}{10000}\Big)\)
\(=log_{2}\Big(\frac{1}{16}\Big)\)
\( =log_{2}{1} - log_{2}16\)
\(=-log_{2}16\)
\(= - \text{ log}_{2}2^4\)
\(=-4\text{ log}_{2}2\)
=-4
General Aptitude, Mathematical Operations, RRB Junior Clerk Exam (Allahabad) 2009, Simplification, Solved
$$\frac{180 \times 15- 12 \times 20}{ 140 \times 8 + 2 \times 55} = ?$$
Nithin K ? Apr 21 '2018 at 17:46
Correct Answer: C [2]
Explanation:
\(\frac{180 \times 15 - 12 \times 20}{140 \times 8 + 2 \times 55}\)
\(=\frac{20 \times 3 [9 \times 5-4]}{10[14 \times 8 +1]}\)
\(=\frac{6 \times 41}{112+11}\implies \frac{6 \times 41}{123}\)
\(=6 \times \frac{1}{3}\)
\(=2\)
The gas used to extinguish fire, is
Nithin K ? Apr 21 '2018 at 16:30
Correct Answer: C [Carbon dioxide]
Explanation:
carbon dioxide Sodium bicarbonate, regular or ordinary used on class B and C fires, was the first of the dry chemical agents developed. In the heat of a fire, it releases a cloud of carbon dioxide that smothers the fire. That is, the gas drives oxygen away from the fire, thus stopping the chemical reaction.
Which of the following law not relate to gases?
Nithin K ? Apr 21 '2018 at 16:26
Correct Answer: D [Faraday’s law]
Explanation:
Faraday's laws deals with electrolysis and not with gases.
A does a work in 10 days and b does the same work In 15 days In how many days they together will do the same work?
Nithin K ? Apr 21 '2018 at 16:18
Corrct Answer: B [6 days]
Explanation:
\(\text{A's one day work =}\frac{1}{10}\)
\(\text{B's one day work = }\frac{1}{15}\)
\(\text{(A+B)'s one day's work }\)
\(=\frac{1}{10} + \frac{1}{15}\)
\(=\frac{3+2}{30}\)
\(=\frac{1}{6}\)
\(\therefore \text{A and B together work in 6 days. }\)