Sunday, November 25, 2018
1354 + 1184 = ? % of 5640
1354 + 1184 = ? % of 5640
Nithin K ? Dec 4 '2016 at 20:32
Answer: 45
Explanation:
\(1354 + 1184 = \text{? % of 5640}\)
\(2538 \text{ = ? % of 5640}\)
\(2538 = \frac{5640 \times x}{100} \)
\(x = \frac{2538 \times 100}{5640}\)
\(x= 45\)
45% of 1200 = 54% of ?
45% of 1200 = 54% of ?
Nithin K ? Dec 4 '2016 at 20:16
Answer: 1000
Explanation:
\(45\% \text{ of 1200 = 54% of x }\)
\(45 \times \frac{1200}{100} = 54 \times \frac{x}{100}\)\(45 \times 12 = 0.54 \times x\)
\(x = \frac{45 \times 12}{0.54} = \frac{540}{0.54}\)
\(x = \frac{54000}{54} = 1000\)
Of the two numbers, 48 percent of first number is 60 percent
Of the two numbers, 48 percent of first number is 60 percent of the second number. What is the respective ratio of the first number to the second number?
Nithin K ? Dec 4 '2016 at 19:59
Answer : 5 : 4
Explanation:
Let the numbers be x and y.
48% of x = 60% of y
\(⇒ \frac{x}{y} = \frac{60}{48} = \frac{10}{8} = \frac{5}{4}\)
\(\therefore x : y = 5 : 4\)
The HCF of two numbers is 15 and their LCM is 300. If one of
The HCF of two numbers is 15 and their LCM is 300. If one of the numbers is 60, the other is
Nithin K ? Dec 4 '2016 at 19:23
Answer : 75
Explanation:
\(\text{ First number } \times \text{ Second number }= \text{ LCM } \times \text{ HCF}\)
\(\therefore \text{ Second number }= \frac{ \text{ LCM } \times \text{ HCF}}{ \text{ First number } }\)
Given, First Number = 60, HCF =15, LCM = 300
\(\therefore \text{ Second number }= \frac{ \text{ 300 } \times \text{ 15 }}{ \text{60 } }\)
\(\therefore \text{ Second number = 75}\)
When simplified the product gives
When simplified the product gives!doctype>?xml>
If the students of a class can be grouped exactly into 6
If the students of a class can be grouped exactly into 6 or 8 or 10, then the minimum number of students in the class must be
Nithin K ? Dec 4 '2016 at 18:59
Answer : 120
Explanation:
Because the required number of students = LCM of 6, 8, 10 = 120.
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