REAR

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RRB TA Exam (Chennai) 2008 click here to view all questions

Choose the alternative which is most opposite in meaning of the word given in capitals.
REAR

AFront

BForeground

CForehead

DForward

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PIVOTAL

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Choose the alternative which is most opposite in meaning of the word given in capitals. PIVOTAL

AStable

BTrivial

CMusical

DMelodious

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EXECRABLE

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Choose the alternative which is most opposite in meaning of the word given in capitals. EXECRABLE

AImportable

BAcceptable

CDesirable

DIrritable

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HUMBLE

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Choose the alternative which is most opposite in meaning of the word given in capitals. HUMBLE

ADominant

BProud

CDespotic

DPompous

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Which number is 60% less than 80?

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RRB TA Exam (Chennai) 2008 click here to view all questions

Which number is 60% less than 80?

A24

B28

C32

D36

Nithin K ? Dec 5 '2016 at 21:36

Answer: 32

Explanation:

\(answer = 80 - \text{60% of 80 }\)

\(answer= 80 - \frac{60 \times 80}{100} \)

\(answer= 80 - 48\)

\(answer= 32\)

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is equal to

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RRB TA Exam (Chennai) 2008 click here to view all questions

A1

B1.5

C2

D2.5

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If the compound interest on a sum for 2 yr at 12.5% per anum

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If the compound interest on a sum for 2 yr at 12.5% per annum is Rs.510, the simple interest on the same sum at the same rate for the same period of time is

ARs.400

BRs.480

CRs.450

DRs.460

Md Hasnain Reza ? Mar 23 '2018 at 17:5

Correct answer is: Rs.480
Explanation: Let's recalculate the answer. We have: - Compound Interest (CI) = Rs. 510 - Time period (T) = 2 years - Rate of interest (R) = 12.5% To find the principal amount (P), we'll use the formula for compound interest: \[CI = P \left(1 + \frac{R}{100}\right)^T - P\] Substituting the given values: \[510 = P \left(1 + \frac{12.5}{100}\right)^2 - P\] Let's first calculate \(\left(1 + \frac{12.5}{100}\right)^2\): \[\left(1 + \frac{12.5}{100}\right)^2 = \left(1.125\right)^2 = 1.265625\] So, the equation becomes: \[510 = P \times 1.265625 - P\] \[510 = 1.265625P - P\] \[510 = 0.265625P\] Now, divide both sides by \(0.265625\) to find \(P\): \[P = \frac{510}{0.265625}\] \[P ≈ 1919.047619\] Now that we have the principal amount (\(P\)), let's calculate the simple interest (SI) using the formula: \[SI = P \times R \times T\] Substituting the values of \(P\), \(R\), and \(T\): \[SI = 1919.047619 \times \frac{12.5}{100} \times 2\] \[SI ≈ 479.7619\] Rounding to the nearest rupee, the simple interest is approximately Rs. 480. Therefore, the correct answer is option B. Rs. 480. Thank you for your patience, and I apologize for any confusion caused.

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