The city was kept .......... night curfew for several days.

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Choose the most suitable alternative to fill in the blank.
The city was kept .......... night curfew for several days.

Aon

Bat

Cunder

Dover

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Do not take leave .......... me, I will be left alone.

Aby

Bof

Coff

Dfrom

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A and B together can complete a work in 3 days.

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RRB TC CC Exam (Chandigarh) 2008 click here to view all questions

A and B together can complete a work in 3 days. They start together but after 2 days, B left the work. If the work is completed after two more days, B alone could do the work in

A5 days

B6 days

C9 days

D10 days

Nithin K ? Apr 7 '2018 at 19:44

Answer is : 6 days

Explanation:

(A+B)'s one day's work \(= \frac{1}{3}\) part
(A+B) works 2 days together \(= \frac{2}{3}\) part;
Remaining work \(= 1-\frac{2}{3} \implies \frac{1}{3} \)part;
1/3 part of work is completed by A in two days;
Hence, one day's work of A = \(\frac{1}{6}\);
Then, one day's work of B\( = \frac{1}{3}-\frac{1}{6}\implies \frac{1}{6}\);
So, B alone can complete the whole work in 6 days.

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What part of a ditch, 48 m long 16.5 m broad and 4 m deep can be filled

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What part of a ditch, 48 m long 16.5 m broad and 4 m deep can be filled by the earth got by digging a cylindrical tunnel of diameter 4 m and length 56 m ?

A$$\frac{1}{9}$$

B$$\frac{2}{9}$$

C$$\frac{7}{9}$$

D$$\frac{8}{9}$$

Nithin K ? Apr 7 '2018 at 16:54

Answer is : b.) \(\frac{2}{9}\)

Explanation:

Volume of the earth dugout as a tunnel = πr2h

= \(\Big(\frac{22}{7}\Big) \times 2 \times 2 \times 56 \)

= \(\text{704 }m^3 \)
\(\text{Volume of the ditch = }\frac{(48 \times 33)}{(2)}\times 4 \implies 24 \times 33 \times 4 \implies \text{3168 }m^3 \)
∴ \(\text{Part required = }\frac{704}{3168} \implies \frac{2}{9}\)

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The area of circle is increased by 22 cm. its radius is increased by 1 cm. The original radius of the circle is

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The area of circle is increased by 22 cm. its radius is increased by 1 cm. The original radius of the circle is

A6 cm

B3.2 cm

C3 cm

D3.5 cm

Nithin K ? Apr 7 '2018 at 16:39

Answer is : c.) 3 cm

Explanation:

Let original radius be r.

Then, according to the question,
\(\Large \pi (r+1)^{2}-\pi r^{2} =22\)

\(\implies \Large \pi\times [(r+1)^{2}-r^{2}] =22\)

\(\implies \Large \frac{22}{7}\times (r+1+r)(r+1-r) =22\)

\(\implies 2r+1=7 \implies 2r=6\)

\(r= \Large \frac{6}{2} =\text{3 cm}\)

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The perimeter of the floor of a room is 18 metres.

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The perimeter of the floor of a room is 18 metres. What is the area of the walls of the room. If the height of the room is 3 metres?

A$$21 m^2$$

B$$42 m^2$$

C$$54 m^2$$

D$$108 m^2$$

Nithin K ? Apr 7 '2018 at 16:11

Answer is : c.) \(54\text{ m}^2\)

Explanation:

If the floor is in rectangular shape

Then your answer is, 

Perimeter of rectangle =2(l+b) 

18=2(l+b) 

Then, 

\(\text{Area of four walls =}2(l+b)\times h\)

\(\text{Area of four walls=}18\times3 \)
\(\text{Area of four walls = }54\text{ m²}\)

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A train travelling at a speed of 30 m/s crosses a platform, 600 m. long, in 30 sec

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A train travelling at a speed of 30 m/s crosses a platform, 600 m. long, in 30 sec.The length (in metres) of train is

A120

B150

C200

D300

Nithin K ? Apr 7 '2018 at 16:2

Answer is : B.) 150

Explanation:

Let the length of the train is x meter and Speed of the train is y meter/second
Then \(\frac{x}{y} = 15\) [because \(\frac{distance}{speed} = time\)] 
\(\implies y = \frac{15}{x}\)

\(\begin{aligned} => \frac{x+100}{25} = \frac{x}{15} \\ x = 150 \text{ meters} \end{aligned}\)

So length of the train is 150 meters

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