12 men can do a piece of work in 10 days. How many men would be required to do the same work in 8 days ?
12 men can do a piece of work in 10 days. How many men would be required to do the same work in 8 days ?
12 men can do a piece of work in 10 days. How many men would be required to do the same work in 8 days ?
‘A’ can complete a piece of work in 12 days. ‘A’ and ‘B’ together can complete the same piece of work in 8 days. In how many days can ‘B’ alone complete the same piece of work ?
12 men take 36 days to do a work while 12 women complete $\frac{3}{4}$ th of the same work in 36 days. In how many days 10 men and 8 women together will complete the same work ?
Three men, four women and six children can complete a work in 7 days. A woman does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 7 days ?
rupa ? Jan 31 '2020 at 22:21
Correct answer is: 7
Explanation:
\(\text{2 men = 1 woman}\)
\(\therefore \text{1 man =} \frac{1}{2} \text{ woman}\)
\(\therefore \text{3 man =} \frac{3}{2} \text{ woman}\)
\(\text{Again, 2 children = 1 man}\)
\(= \frac{1}{2} \text{ woman}\)\(\therefore \text{1 child = } \frac{1}{4} \text{ woman}\)
\(\therefore \text{6 children = }\frac{6}{4} = \frac{3}{2} \text{women}\)
Now, three men, four women and six children
\(= \frac{3}{2} + 4 + \frac{3}{2} =\text{ 7 women}\)Hence, 7 women complete the work in 7 days.
A and B together can complete a task in 20 days. B and C together can complete the same task in 30 days. A and C together can complete the same task in 40 days. What is the respective ratio of the number of days taken by A when completing the same task alone to the number of days taken by C when completing the same task alone ?
Akilesh Kharvi ? May 29 '2017 at 22:31
Answer is 1 : 5
Explanation:
(A + B)’s 1 day’s work = \(\frac{1}{20}\)
(B + C)’s 1 day’s work = \(\frac{1}{30}\)
(C + A)’s 1 day’s work = \(\frac{1}{40}\)
On adding,2(A + B + C)’s 1 day’s work
= \(\frac{1}{20}+\frac{1}{30}+\frac{1}{40}\)
= \(\frac{6+4+3}{120}\) = \(\frac{13}{120}\)
(A + B + C)’s 1 day’s work= \(\frac{13}{240}\)
A’s 1 day’s work
= \(\frac{13}{240}-\frac{1}{30}\)= \(\frac{13-8}{240}\)
= \(\frac{5}{240}= \frac{1}{48}\)
C’s 1 day’s work
= \(\frac{13}{240}-\frac{1}{20}= \frac{13-12}{240} = \frac{1}{240}\)
Required ratio = 48 : 240 = 1 : 5
Four examiners can examine a certain number of answer papers in 10 days by working for 5 hours a day. For how many hours in a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days ?
6 women and 6 men together can complete a piece of work in 6 days. In how many days can 15 men alone complete the piece of work if 9 women alone can complete the work in 10 days ?
Akilesh Kharvi ? May 29 '2017 at 22:13
Answer is 4
Explanation:
9 women can complete the work in10 days.
6 women can complete the work in \(\frac{10\times9}{6}\) = 15 days.
Part of work done by 6 women = \(\frac{6}{15}\) =\(\frac{2}{5}\)
Part of work done by 6 men =\( 1 - \frac{2}{5} = \frac{3}{5}\)
\(\frac{3}{5}\) part of work done by 6 men in 1 days.
1 part of work done by 6 men in \(\frac{6}{3}\) × 5= 10 days.
15 men can complete the work in \(\frac{10\times6}{15}\)
= 4 days