The present ages of Amit and his father are in the ratio of 2 : 5 respectively. Four years hence the ratio of their ages will become 5 : 11 respectively. What was the father's age five years ago?

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BANK PO Exam (Andhra Bank) 2009 click here to view all questions

The present ages of Amit and his father are in the ratio of 2 : 5 respectively. Four years hence the ratio of their ages will become 5 : 11 respectively. What was the father's age five years ago?

A 40 yr

B45 yr

C30 yr

D35 yr

Nithin ? Aug 14 '2022 at 21:1

Correct answer is: 35 yr

Explanation:

Suppose the present age of Amit and his father is 2x and 5x respectively.
After 4 years the ratio of their ages,

(2x+4):(5x+4)= 5:11
\(25x + 20 = 22x+44\)

\(25x-22x=44-20\)

\(3x=24\)

\(x=8\)

Age of his father before 5 years

\(=5x-5\)

\(=5 \times 8 -5\)

\(= 40 - 5\)

= 35 yr

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Ratio of Rams and Komars age is 3 : 5 respectively. Ratio of Komal's and Pooja's age is 2 : 3 respectively. If Rani is two-fifth of Pooja's age. what is Rani's age?

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Ratio of Rams and Komars age is 3 : 5 respectively. Ratio of Komal's and Pooja's age is 2 : 3 respectively. If Rani is two-fifth of Pooja's age. what is Rani's age?

A10 years

B15 years

C24 years

DCannot be determined

Nithin ? Aug 14 '2022 at 16:38

Correct answer is: Cannot be determined

Explanation:

Rani : Komal = \(3 : 5 = 6 : 10\)

Komal : Pooja = \( 2 : 3 = 10 : 15\)

Therefore, Rani : Kornal : Pooja = \(6 : 10 : 15\)

We have insufficient data to solve this question.

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The ratio of the age of a father and son is 17 : 7 respectively. 6 years ago the ratio of their age was 3 : 1 respectively. What is the father's present age?

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The ratio of the age of a father and son is 17 : 7 respectively. 6 years ago the ratio of their age was 3 : 1 respectively. What is the father's present age?

A64 yrs

B51 yrs

C48 yrs

DCannot be determined

Nithin ? Aug 14 '2022 at 15:52

Correct answer is: 51 yrs

Explanation:

Let the present age of father and son be 17x years and 7x years respectively.

According to the question,

\(\Large \frac{17x-6}{7x-6}=\frac{3}{1}\)
\(\implies 21x - 18 = 17x - 6\)
\(\implies 21x - 17x = 18 - 6\)

\(\implies 4x = 12\)

\(=> x = \frac{12}{4} = 3\)

\(\text{Therefore, Father's present age} = 17×3 = 51 \text{ years}\)

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The age of Sonal and Nitya are in the ratio of 9 : 5 respectively. After 8 years the ratio of their ages will be 13 : 9. What is the difference in years between their ages?

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The age of Sonal and Nitya are in the ratio of 9 : 5 respectively. After 8 years the ratio of their ages will be 13 : 9. What is the difference in years between their ages?

A4 years

B12 years

C6 years

DNone of these

Nithin ? Aug 14 '2022 at 15:40

Correct answer is: None of these

Explanation:

The age of Sonal and Nitya are in the ratio of 9:5 respectively

Let x be an arbitrary constant,

Age of Sonal is 9x and age of Nitya is 5x.

After 8 years the ratio of their age is 13 : 9

Now,

After 8 years Sonal’s age will be (9x + 8)

After 8 years Nitya’s age will be (5x + 8)

According to the question

\(\frac{{\left( {9x\; + \;8} \right)}}{{\left( {5x\; + \;8} \right)}}\; = \;\frac{{13}}{9}\)

\(⇒ 81x + 72 = 65x + 104\)

\(⇒ 16x = 32\)

\(⇒ x = 2\)

Sonal’s age is 9 × 2 = 18 years

Nitya’s age is 5 × 2 = 10 years

And their age difference is (18 - 10) years = 8 years

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The ages of Sulekha and Arunima are in the ratio 9 : 8 respectively. After 5 years, the ratio of their ages will be 10 : 9. What is the difference in their ages ?

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The ages of Sulekha and Arunima are in the ratio 9 : 8 respectively. After 5 years, the ratio of their ages will be 10 : 9. What is the difference in their ages ?

A4 years

B5 years

C6 years

D7 years

Nithin ? Aug 14 '2022 at 11:47

Correct answer is: 5 years

Explanation:

Let Sulekha age be 9 year,
Then Arunima's age = 8x years

\(\eqalign{ & \frac{{9x + 5}}{{8x + 5}} = \frac{{10}}{9} \cr & \Rightarrow 9\left( {9x + 5} \right) = 10\left( {8x + 5} \right) \cr & \Rightarrow 81x + 45 = 80x + 50 \cr & \Rightarrow x = 5 \cr}\)

Difference in their ages
= (9x - 8x) years
= x years
= 5 years

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The ratio between the adjacent angles of a parallelogram is 7 : 8 respectively. Also the ratio between the angles of quadrilateral is 5 : 6 : 7 : 12. What is the sum of the smaller angle of parallelogram and second largest angle of the quadrilateral?

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The ratio between the adjacent angles of a parallelogram is 7 : 8 respectively. Also the ratio between the angles of quadrilateral is 5 : 6 : 7 : 12. What is the sum of the smaller angle of parallelogram and second largest angle of the quadrilateral?

A168°

B228°

C156°

D224°

Nithin ? Aug 14 '2022 at 11:8

Correct answer is: 168°

Explanation:

 

Let the adjacent angles be \(7x^∘\text{and }8x^∘\)

Therefore, 7x + 8x = 180

=> 15x = 180

=> x = 12

Therfore, Smaller angle = 7 x 12 = 84°

Again. 5y + 6y + 7y + 12y = 360°

=> 30y = 360°

= y = \(\frac{360}{30}\)

Therefore, Second largest angle of the quadrilateral

= 7×12 = \(84^o\)

 

Therefore, Required sum = \(84 + 84 = 168^o\)

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The ratio between the three angles of a quadrilateral is 13 : 9 : 5 respectively. The value of the fourth angle of the quadrilateral is 36∘C. What is the difference between the largest and the second smallest angles of the quadrilateral?

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The ratio between the three angles of a quadrilateral is 13 : 9 : 5 respectively. The value of the fourth angle of the quadrilateral is 36∘C. What is the difference between the largest and the second smallest angles of the quadrilateral?

A104°

B 108°

C72°

D 96°

Nithin ? Aug 14 '2022 at 10:10

Corect answre is: 96°

Explanation:

Let the three angles of quadrilateral be

\(13x^∘, 9x^∘,\text{ and }5x^∘ \text{ respectively.}\)

\(\text{Therefore, } 13x + 9x + 5x = 360 - 36\)

\(\implies 27x = 324 \implies x = \frac{324}{27} =12\)

Therefore, Required difference

\(=13x - 5x = 8x = 8\times \text{12 }= 96^∘\)

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