In two vessels A and B. there is mixture of milk and water. The ratio of milk and water in these vessels is 5 : 2 and 8 : 5 respectively. In what ratio these mixtures be mixed together so that the ratio of milk and water in the new mixture becomes 9 : 4?

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In two vessels A and B. there is mixture of milk and water. The ratio of milk and water in these vessels is 5 : 2 and 8 : 5 respectively. In what ratio these mixtures be mixed together so that the ratio of milk and water in the new mixture becomes 9 : 4?

A7 : 2

B2 : 7

C3 : 5

D5 : 3

Nithin ? undefined

Correct answer is: 7 : 2

Explanation:

Let. C.P. of milk per litre be Re.1

 \(\text{Milk in 1 litre of A = }\frac{5}{7} \text{ litre}\) 

\(\text{Milk in 1 litre of B }= \frac{8}{13}\)

\(\text{Milk in 1 litre of mixture }= \frac{9}{13} litre\)

\(\text{Therefore, Required ratio}\)

\(= \frac{1}{13} : \frac{2}{91}\)

\(= 7 : 2\)

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A sum of Rs.221 is divided among X, Y and Z such that X gets Rs.52 more than Y, Y gets Rs.26 more than Z. The ratio of the shares of X, Y and Z respectively is:

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A sum of Rs.221 is divided among X, Y and Z such that X gets Rs.52 more than Y, Y gets Rs.26 more than Z. The ratio of the shares of X, Y and Z respectively is:

A9 : 5 : 3

B9 : 3 : 5

C5 : 9 : 3

D10 : 6 : 5

Nithin ? undefined

Correct answer is: 9 : 5 : 3

Explanation:

x = y + 52

z = y - 26

Therefore, x + y + z = 221

=> y + 52 + y + y - 26 = 221

=> 3y = 221 - 26 =195

\(=> y = \frac{195}{3} = 65\)

Therefore, x = 65 + 52 = 117

z = 65 - 26 = 39
x : y : z = 117 : 65 : 39

= 9 : 5 : 3

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The average age of a man and his son is 30 years. The ratio of their age tom-years ago was 10 : 3 respectively. What is the difference between the present age of the man and his son?

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The average age of a man and his son is 30 years. The ratio of their age tom-years ago was 10 : 3 respectively. What is the difference between the present age of the man and his son?

A28 years

B16 years

C26 years

D44 years

Nithin ? undefined

Correct answer is: 28 years

Explanation:

Four years ago,

Let, Father's age = 10x years

Son's age = 3x years

Therefore, 10x + 3x + 8 = 60

=>13x = 60 - 8 = 52 => x = 4

Therefore, Required difference = 7x = 7×4 = 28 years

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A particular sum was divided among A, B and C in the ratio 2 : 6 : 7 respectively. If the amount received by A was Rs.4,908, what was the difference between the amount received by B and C?

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A particular sum was divided among A, B and C in the ratio 2 : 6 : 7 respectively. If the amount received by A was Rs.4,908, what was the difference between the amount received by B and C?

ARs.2,454

BRs.3,494

CRs.2,135

DRs.2,481

Nithin ? undefined

Correct answer is: Rs.2,454

Explanation:

If the total amount be Rs.2,
\(\text{then }\frac{2x}{15}=4908\)
\(\implies x = \frac{4908 \times 15}{2} \text{= Rs.36810}\)

Therefore, Required difference

\(= \frac{7-6}{16} \times 36810 = \text{ Rs. 2454}\)

 

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A certain amount was to be distributed among A, B and C in the ratio 2 : 3 : 4 respectively. but was erroneously distributed in the ratio 7 : 2 : 5 respectively. As a result of this, B got Rs.40 less. What is the amount?

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A certain amount was to be distributed among A, B and C in the ratio 2 : 3 : 4 respectively. but was erroneously distributed in the ratio 7 : 2 : 5 respectively. As a result of this, B got Rs.40 less. What is the amount?

ARs.210

BRs.270

CRs.230

DRs.280

Nithin ? undefined

Correct answer is: Rs.210

Explanation:

Let the amount be Rs.x.

\(\therefore \left(\frac{3}{9}-\frac{2}{14}\right)x = 40\)

\( \left(\frac{1}{3}-\frac{1}{7}\right)x = 40 \implies \left(\frac{7-3}{21}\right)x = 40\)

\(x = \frac{40 \times 21}{4}\)

\(\text{= Rs.210}\)

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When X is subtracted from the numbers 9, 15 and 27, the remainders are in continued proportion. What is the value of X?

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When X is subtracted from the numbers 9, 15 and 27, the remainders are in continued proportion. What is the value of X?

A8

B6

C4

DNone of these

Nithin ? undefined

Correct answer is: None of these

Explanation:

\(\Large \frac{9-x}{15-x}=\frac{15-x}{27-x}\)

\(\Large 243 - 9x - 27x + x^{2}\)

\(\Large 225 - 30x + x^{2}\)

\( 6x = 243 - 225 = 18\)

\(x = 3\)

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Rita invested 25% more than sunil. Sunil invested 30% less than Abhinav, who invested Rs. 6000. What is the ratio of the amount that Rita invested to the total amount by all of them together ?

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Rita invested 25% more than sunil. Sunil invested 30% less than Abhinav, who invested Rs. 6000. What is the ratio of the amount that Rita invested to the total amount by all of them together ?

A35 : 104

B13 : 29

C101 : 36

D35 : 103

Nithin ? undefined

Correct answer is: 35 : 103

Explanation:

Abhinav's investment = Rs.6000

Sunil's investment = \(\Large \frac{70 \times 6000}{100}\) = Rs. 4200

Rita's investment = \(\Large \frac{4200 \times 125}{100}\) = Rs.5250

Therefore, Required ratio = \(\Large 5250 : \left(6000+4200+5250\right)\)

= 5250 : 15450 = 35 : 103

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