If 50% of a certain number is equal to 3/4 th of another number, what is the ratio between the numbers?
If 50% of a certain number is equal to 3/4 th of another number, what is the ratio between the numbers?
If 50% of a certain number is equal to 3/4 th of another number, what is the ratio between the numbers?
Nithin ? undefined
Correct answer is: 3 : 2
Explanation:
Let, First number = x
Second number = y\(\therefore x \times \frac{50}{100}=y \times \frac{3}{4}\)
\(\implies \frac{x}{2}=y \times \frac{3}{4}\)
\(\implies \frac{x}{y}=\frac{3}{4} \times 2=\frac{3}{2} \text{ or}\ 3 : 2\)
In two vessels A and B. there is mixture of milk and water. The ratio of milk and water in these vessels is 5 : 2 and 8 : 5 respectively. In what ratio these mixtures be mixed together so that the ratio of milk and water in the new mixture becomes 9 : 4?
Nithin ? undefined
Correct answer is: 7 : 2
Explanation:
Let. C.P. of milk per litre be Re.1
\(\text{Milk in 1 litre of A = }\frac{5}{7} \text{ litre}\)
\(\text{Milk in 1 litre of B }= \frac{8}{13}\)
\(\text{Milk in 1 litre of mixture }= \frac{9}{13} litre\)
\(\text{Therefore, Required ratio}\)
\(= \frac{1}{13} : \frac{2}{91}\)
\(= 7 : 2\)
A sum of Rs.221 is divided among X, Y and Z such that X gets Rs.52 more than Y, Y gets Rs.26 more than Z. The ratio of the shares of X, Y and Z respectively is:
Nithin ? undefined
Correct answer is: 9 : 5 : 3
Explanation:
x = y + 52
z = y - 26
Therefore, x + y + z = 221
=> y + 52 + y + y - 26 = 221
=> 3y = 221 - 26 =195
\(=> y = \frac{195}{3} = 65\)
Therefore, x = 65 + 52 = 117
z = 65 - 26 = 39
x : y : z = 117 : 65 : 39= 9 : 5 : 3
The average age of a man and his son is 30 years. The ratio of their age tom-years ago was 10 : 3 respectively. What is the difference between the present age of the man and his son?
Nithin ? undefined
Correct answer is: 28 years
Explanation:
Four years ago,
Let, Father's age = 10x years
Son's age = 3x years
Therefore, 10x + 3x + 8 = 60
=>13x = 60 - 8 = 52 => x = 4
Therefore, Required difference = 7x = 7×4 = 28 years
A particular sum was divided among A, B and C in the ratio 2 : 6 : 7 respectively. If the amount received by A was Rs.4,908, what was the difference between the amount received by B and C?
Nithin ? undefined
Correct answer is: Rs.2,454
Explanation:
If the total amount be Rs.2,
\(\text{then }\frac{2x}{15}=4908\)
\(\implies x = \frac{4908 \times 15}{2} \text{= Rs.36810}\)Therefore, Required difference
\(= \frac{7-6}{16} \times 36810 = \text{ Rs. 2454}\)
A certain amount was to be distributed among A, B and C in the ratio 2 : 3 : 4 respectively. but was erroneously distributed in the ratio 7 : 2 : 5 respectively. As a result of this, B got Rs.40 less. What is the amount?
Nithin ? undefined
Correct answer is: Rs.210
Explanation:
Let the amount be Rs.x.
\(\therefore \left(\frac{3}{9}-\frac{2}{14}\right)x = 40\)
\( \left(\frac{1}{3}-\frac{1}{7}\right)x = 40 \implies \left(\frac{7-3}{21}\right)x = 40\)
\(x = \frac{40 \times 21}{4}\)
\(\text{= Rs.210}\)
When X is subtracted from the numbers 9, 15 and 27, the remainders are in continued proportion. What is the value of X?
Nithin ? undefined
Correct answer is: None of these
Explanation:
\(\Large \frac{9-x}{15-x}=\frac{15-x}{27-x}\)
\(\Large 243 - 9x - 27x + x^{2}\)
\(\Large 225 - 30x + x^{2}\)
\( 6x = 243 - 225 = 18\)
\(x = 3\)