Income of two companies A and B are in the ratio of 5 : 8. Had the income of company 'A' been more by Rs.25 lakhs, the ratio of their income would have been 5 : 4 respectively. What is the income of company 'B'?

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Income of two companies A and B are in the ratio of 5 : 8. Had the income of company 'A' been more by Rs.25 lakhs, the ratio of their income would have been 5 : 4 respectively. What is the income of company 'B'?

ARs.80 lakhs

BRs.50 lakhs

CRs.40 lakhs

DRs.60 lakhs

Nithin ? undefined

Correct answer is: Rs.40 lakhs

Explanation:

A : B = 5 : 8
Let A's income be 5x and B's income be 8x.
According to question.

\(\Large \frac{5x+25}{8x}=\frac{5}{4}\)

\(\frac{5 \left(x+5\right) }{4 \times 2x}=\frac{5}{4} => \frac{x+5}{2x} = 1\)

x + 5 = 2x
x = 5

\(\text{B's Income} = 8x = 8×5\)

= Rs.40 lakhs.

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In a school the number of boys and that of the girls are in the respective ratio of 2 : 3. If the number of boys is increased by 20% and that of girls is increased by 10%, what will be the new ratio of number of boys to that of the girls?

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In a school the number of boys and that of the girls are in the respective ratio of 2 : 3. If the number of boys is increased by 20% and that of girls is increased by 10%, what will be the new ratio of number of boys to that of the girls?

A14 : 5

B5 : 8

C13 : 4

DNone of these

Nithin ? undefined

Correct answer is: None of these

Explanation:

Ratio of no. boys : girls = 2 : 3
Let the no. of boys = 2x
Then the no. of girls = 3x
No. of boys after 20% increase = 1.20 x 2x = 2.4 x.
No. of girls after 10% increase = 1.10 x 3x = 3.3x
Required ratio

\(= \frac{2.4x}{3.3x}=\frac{8}{11} = 8 : 11\)

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A sum of money is to be distributed among P, Q and R in the ratio 6 : 19 : 7. If R gives Rs.200 from his share to Q. the ratio of P, Q and R becomes 3 : 10 : 3. what is the total sum?

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A sum of money is to be distributed among P, Q and R in the ratio 6 : 19 : 7. If R gives Rs.200 from his share to Q. the ratio of P, Q and R becomes 3 : 10 : 3. what is the total sum?

ARs. 6400

BRs.12800

CRs. 3200

DData inadequate

Nithin ? undefined

Correct answer is: Rs. 6400

Explanation:

Let P's share be 6x
Q's share be 19x and
R's share be 7x.
Total sum = 6x + 19x + 7x = 32x
6x : 19x + 200 : 7x - 200
= 3 : 10 : 3
We can write
6x = 7x - 200 => x = 200
Total sum = 32x = Rs.6400

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When a number is added to a second number, the sum is 333 1/3 percent of the second number. What is the ratio between the first number to the second number?

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When a number is added to a second number, the sum is $333\frac{1}{3}$ percent of the second number. What is the ratio between the first number to the second number?

A3 : 7

B7 : 4

C7 : 3

DData inadequate

Nithin ? undefined

Correct answre is: 7 : 3

Explanation:

Let the first number be x
and the second number be y

 

x + y =  \(333\frac{1}{3}\) % of y

\(x + y = \frac{1000}{3 \times 100}y\)

\(x+y = \frac{10}{3}y\)

3x + 3y = 10y
3x = 7y

\( \frac{x}{y}=\frac{7}{3}= 7 : 3\)

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The ratio of the present age of Mahesh and Ajay is respectively 3 : 2. After 8 years, ratio of their age will be 11 : 8. What will be the present age of Mahesh's son if his age is half of the present age of Ajay?

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The ratio of the present age of Mahesh and Ajay is respectively 3 : 2. After 8 years, ratio of their age will be 11 : 8. What will be the present age of Mahesh's son if his age is half of the present age of Ajay?

A12 years

B24 years

C18 years

D9 years

Nithin ? undefined

Correct answer is: 12 years

Explanation:

Let, Mahesh => 3x years
Ajay => 2x years
After 8 years.

\( \frac{3x+8}{2x+8}=\frac{11}{8}\)

=> 24x + 64 = 22x + 881
=> 2x = 88 - 64 = 24
=> x = 12

=> Therefore, Ajay's age 2x = \(2 \times 12\) = 24 years
Therefore, Age of Mahesh's son
\(= \frac{1}{2} \times 24\)

= 12 years

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If 50% of a certain number is equal to 3/4 th of another number, what is the ratio between the numbers?

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If 50% of a certain number is equal to 3/4 th of another number, what is the ratio between the numbers?

A3 : 2

B2 : 5

C5 : 2

D3 : 4

Nithin ? undefined

Correct answer is: 3 : 2

Explanation:

Let, First number = x
Second number = y

\(\therefore x \times \frac{50}{100}=y \times \frac{3}{4}\)

\(\implies \frac{x}{2}=y \times \frac{3}{4}\)

\(\implies \frac{x}{y}=\frac{3}{4} \times 2=\frac{3}{2} \text{ or}\ 3 : 2\)

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In two vessels A and B. there is mixture of milk and water. The ratio of milk and water in these vessels is 5 : 2 and 8 : 5 respectively. In what ratio these mixtures be mixed together so that the ratio of milk and water in the new mixture becomes 9 : 4?

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In two vessels A and B. there is mixture of milk and water. The ratio of milk and water in these vessels is 5 : 2 and 8 : 5 respectively. In what ratio these mixtures be mixed together so that the ratio of milk and water in the new mixture becomes 9 : 4?

A7 : 2

B2 : 7

C3 : 5

D5 : 3

Nithin ? undefined

Correct answer is: 7 : 2

Explanation:

Let. C.P. of milk per litre be Re.1

 \(\text{Milk in 1 litre of A = }\frac{5}{7} \text{ litre}\) 

\(\text{Milk in 1 litre of B }= \frac{8}{13}\)

\(\text{Milk in 1 litre of mixture }= \frac{9}{13} litre\)

\(\text{Therefore, Required ratio}\)

\(= \frac{1}{13} : \frac{2}{91}\)

\(= 7 : 2\)

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