Three-fourth of a number is equal to 60% of another number. What is the difference between the numbers?
Three-fourth of a number is equal to 60% of another number. What is the difference between the numbers?
Three-fourth of a number is equal to 60% of another number. What is the difference between the numbers?
Nithin ? undefined
Correct answre is: Cannot be determined
Explanation:
Let the numbers be x and y respectively . Then,
\(\Large \frac{3}{4}x = \text{= 60% of y}\)
\(= \Large \frac{3}{4}x = \frac{60}{100}y \implies \frac{3}{4}x = \frac{3}{5}y\)
\(=\Large y = \frac{3}{4} \times \frac{5}{3}x = \frac{5}{4}x\)
\(\therefore \Large y - x = \frac{5}{4}x-x = \frac{x}{4}\)
Clearly, no unique answer is possible.
The present age of A, B, C are in the ratio 8:14:22 respectively.the present ages of B, C and D are in the ratio 21:33:44 respectively. Which of the following represents the ratio of he present ages of A, B, C and D respectively
Nithin ? undefined
Correct answer is: 12:21:33:44
Explanation:
A : B : C = 8 : 14 : 22
or 4 : 7 : 11
or 12 : 21 : 33
B : C : D = 21 : 33 : 44
Therefore, A : B : C : D
= 12 : 21 : 33 : 44
The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?
Nithin ? undefined
Correct answer is: 23 : 33 : 60
Explanation:
\(\eqalign{ & {\text{Let}}, \cr & A = 2k \cr & B = 3k\,{\text{and}} \cr & C\, = 5k \cr & A's\,{\text{new}}\,{\text{salary}} \cr & = \frac{{115}}{{100}}\,of\,2k = {\frac{{115}}{{100}} \times 2k} = \frac{{23k}}{{10}} \cr & B's\,{\text{new}}\,{\text{salary}} \cr & = \frac{{110}}{{100}}\,of\,3k = {\frac{{110}}{{100}} \times 3k} = \frac{{33k}}{{10}} \cr & C's\,{\text{new}}\,{\text{salary}} \cr & = \frac{{120}}{{100}}\,of\,5k = {\frac{{120}}{{100}} \times 5k} = 6k \cr & \therefore {\text{New}}\,{\text{ratio}} \cr & = {\frac{{23k}}{{10}}:\frac{{33k}}{{10}}:6k} \cr & = 23:33:60 \cr} \)
The ratio of the earnings of A and B is 4:7. If the earnings A increase by 50% and those of B decrease by 25%, the new ratio of their earnings becomes 8:7. What areA's earnings?
Nithin ? undefined
Correct answer is: Data inadequate
Explanation:
The ratio of the earnings of A and BB is 4:7
Let Earnings of A=4k
Earnings of B=7k
Earnings of A now becomes 4k+\(\frac{1}{2}\)×4k=4k+2k=6k
Earnings of B now becomes 7k−\(\frac{1}{4}\)×7k=\(\frac{3}{4}\)×7k=\(\frac{21k}{4}\)
Now ratio of earnings are \(\frac{6}{\frac{21}{4}}\)=\(\frac{24}{21}\)=\(\frac{8}{7}\)
Hence the Data is Inadequate.
The number of employees shed through voluntary retirement in company A was 23,000 and that in company B was 6325. What is the ratio of employees retired voluntarily from company A to that retired from company B?
Nithin ? undefined
Correct answer is: 40 : 11
Explanation:
Required ratio
\(= \Large \frac{23000}{6325}=\frac{40}{11}\) or 40 : 11
In a college, the ratio of boys to girls is 31 : 23 respectively. When 75 more girls join the college, this ratio becomes 124 : 107. How many more girls should join the college to make the number of boys and girls equal?
Nithin ? undefined
Correct answer is: 85
Explanation:
Let the number of boys initially = 31x
=> Number of girls = 23x
Acc to ques,
\(= \frac{31x}{23x + 75} = \frac{124}{107}\)
= 3317x = 2852x + 9300
= 3317x - 2852x = 465x = 9300
\(x = \frac{9300}{465} = 20\)
=> Number of boys = \(31 \times 20 = 620\)
Number of girls = \(23 \times 20 + 75 = 535\)
\(\therefore \) Number of girls who should join the college to make number of boys and girls equal
= 620 - 535
= 85
Ratio of earnings of A and B is 8 : 9 respectively. If the earnings of A increase by 50% and the earnings of B decrease by 25%, the new ratio of their earnings becomes 16 : 9 respectively. What are A's earnings?
Nithin ? undefined
Correct answer is: Cannot be determine
Explanation:
Let the earnings of A and B Rs. 8x and Rs. 9x respectively.
Then,\(\eqalign{ & = \frac{{150\% {\text{ of }}8x}}{{75\% {\text{ of }}9x}} = \frac{{16}}{9} \cr & \Rightarrow \frac{{\frac{3}{2} \times 8x}}{{\frac{3}{4} \times 9x}} = \frac{{16}}{9} \cr & \Rightarrow \frac{{16}}{9} = \frac{{16}}{9} \cr} \)
Hence, A's earnings cannot be determined