21, 25, 33, 49, 81, (_)

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RRB TA Exam (Chennai) 2008 click here to view all questions

In the following questions, find the number which can be put in the blank to complete the series. 21, 25, 33, 49, 81, (......)

A145

B129

C113

D97

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Answer is : 145 The pattern is + 4, + 8, + 16, + 32,....  $i.e.+2^2,+2^3,+2^4,+2^5,...$ $\therefore \text{Missing number}=81+2^6=81+64$ = 145. Akilesh Kharvi ? answered Sun Oct 16 2016 12:30:00 GMT+0530 (IST) All Comments

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