A student walks from his house at a speed of 2.5

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RRB TC CC Exam (Chandigarh) 2008 click here to view all questions

A student walks from his house at a speed of 2.5 km/h and reaches his school 6 min late. The next day he increases his speed by 1 km/h and reaches 6 min before school time. How far is the school from his house?

A$$\frac{5}{4} km$$

B$$\frac{7}{4} km $$

C$$\frac{9}{4}km$$

D$$\frac{11}{4}km$$

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Answer is $\frac{7}{4} km$ Explanation:   Let the distance be x km   $\text{Distance in timings =12 min =}\frac{12}{60}\text{ hr}=\frac{1}{5} \text{hr}$ $\therefore \frac{2x}{5}-\frac{2x}{7}=\frac{1}{5}$ $14x-10x=7$ $x = 1\frac{3}{4}\text{ km}$ $x= \frac{7}{4}\text{ km}$ Nithin K ? answered Apr 7 '2018 at 20:28 All Comments

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