If the product of two successive positive integers is 7482.

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RRB TA Exam (Chennai) 2008 click here to view all questions

If the product of two successive positive integers is 7482. Which is the greater integer?

A87

B82

C84

D89

Nithin K ? Dec 4 '2016 at 10:14

Answer : 87

Explanation:

Given that \(x(x+1)=7482\)
\(x^2+x=7482\)
\(x^2+x-7482=0 \)
Solve by quadratic equation 

\((x-87)(x+86)=0\)

\(\therefore x=87 \text{ or } x=-86\)

\(\because \text{ the integers are positive the negative option is disregarded. So the answer is 87.}\)

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Answer : 87 Explanation: Given that \(x(x+1)=7482\) \(x^2+x=7482\) \(x^2+x-7482=0 \) Solve by quadratic equation  \((x-87)(x+86)=0\) \(\therefore x=87 \text{ or } x=-86\) \(\because \text{ the integers are positive the negative option is disregarded. So the answer is 87.}\) Nithin K ? answered Dec 4 '2016 at 10:14 All Comments

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