If two numbers be more than a third number by 30% and 40% respectively, the percentage of the first from the second number is

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RRB Junior Clerk Exam (Allahabad) 2009 click here to view all questions

If two numbers be more than a third number by 30% and 40% respectively, the percentage of the first from the second number is

A0.85

B$$92\frac{6}{7} \%$$

C$$79 \frac{1}{2}\% $$

D$$63 \frac{2}{3}\%$$

Nithin K ? Apr 15 '2018 at 12:25

Correct Answer: B [\(92\frac{6}{7}\%\) ]

Explanation:

Let the third number be 100. Then, 
1st number = 130
2nd number = 140
% 1st to the 2nd number =\( \big(\frac{130}{140}\big)\times100 \)

\(= 92(\frac{6}{7})\%\)

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Correct Answer: B [\(92\frac{6}{7}\%\) ] Explanation: Let the third number be 100. Then,  1st number = 130 2nd number = 140 % 1st to the 2nd number =\( \big(\frac{130}{140}\big)\times100 \) \(= 92(\frac{6}{7})\%\) Nithin K ? answered Apr 15 '2018 at 12:25 All Comments

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