If (x:y)=2: 1,then(x^2-y^2): (x^2+ y^2) is

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RRB Junior Clerk Exam (Allahabad) 2009 click here to view all questions

$$If (x:y)=2: 1,then(x^2-y^2): (x^2+ y^2) is: $$

A3:5

B5:3

C1:3

D3:1

Nithin K ? Apr 17 '2018 at 21:20

Correct Answer: 3:5

Explanation:

\(\frac{x}{y}=\frac{2}{1} \text{ (Given)}\)

\(\text{Expression} = \frac{x^2-y^2}{x^2+y^2} = \frac{\frac{x^2}{y^2}-1}{\frac{x^2}{y^2}+1}\)

\(=\frac{(\frac{2}{1})^2-1}{(\frac{2}{1})^2+1}= \frac{4-1}{4+1}=\frac{3}{5}\)

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Correct Answer: 3:5 Explanation: \(\frac{x}{y}=\frac{2}{1} \text{ (Given)}\) \(\text{Expression} = \frac{x^2-y^2}{x^2+y^2} = \frac{\frac{x^2}{y^2}-1}{\frac{x^2}{y^2}+1}\) \(=\frac{(\frac{2}{1})^2-1}{(\frac{2}{1})^2+1}= \frac{4-1}{4+1}=\frac{3}{5}\) Nithin K ? answered Apr 17 '2018 at 21:20 All Comments

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