The length of a rectangle is decreased by 10% and its

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RRB TA Exam (Chennai) 2008 click here to view all questions

The length of a rectangle is decreased by 10% and its breadth is increased by 10%. By what percent is its area changed?

A0%

B1%

C5%

D100%

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Answer is : 1% Explanation: When there is an increase in sides of a figure, the net increase in its area is $= x+y+\frac{xy}{100} \%$ where x and y are length and breadth given, length x decreased by 10. so, x =  -10. breadth y increased by 10. so, y = 10. percent is its area changed $= -10 + 10 + \frac{-10 \times10}{100}\% = -1 \%$ $\therefore \text{ percent of area decresed by 1%}$   Nithin K ? answered Dec 2 '2016 at 23:57 All Comments

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