The length of a rectangle is decreased by 10% and its

Report

Report an issue

Name

Email

Message

Submit

Cancel

RRB TA Exam (Chennai) 2008 click here to view all questions

The length of a rectangle is decreased by 10% and its breadth is increased by 10%. By what percent is its area changed?

A0%

B1%

C5%

D100%

Nithin K ? Dec 2 '2016 at 23:57

Answer is : 1%

Explanation:

When there is an increase in sides of a figure, the net increase in its area is

\(= x+y+\frac{xy}{100} \%\)

where x and y are length and breadth

given, length x decreased by 10. so, x =  -10.

breadth y increased by 10. so, y = 10.

percent is its area changed
\(= -10 + 10 + \frac{-10 \times10}{100}\% = -1 \%\)

\(\therefore \text{ percent of area decresed by 1%}\)

 

All DiscussionsClick here to write answer

Answer is : 1% Explanation: When there is an increase in sides of a figure, the net increase in its area is \(= x+y+\frac{xy}{100} \%\) where x and y are length and breadth given, length x decreased by 10. so, x =  -10. breadth y increased by 10. so, y = 10. percent is its area changed \(= -10 + 10 + \frac{-10 \times10}{100}\% = -1 \%\) \(\therefore \text{ percent of area decresed by 1%}\)   Nithin K ? answered Dec 2 '2016 at 23:57 All Comments

Post your answers here:

Post

Post your comments here:

Message

Post

Cancel