The percentage increase in the area of a rectangle, if each

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RRB TA Exam (Chennai) 2008 click here to view all questions

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is

A40%

B42%

C44%

D46%

Nithin K ? Dec 4 '2016 at 14:38

Answer :  44%

Explanation:

Let original length = x metres and original breadth = y metres.
Original area = \(\text{xy }m^2\)

Increased length  \(= \frac{120}{100}x\)  and Increased breadth \(= \frac{120}{100}y\)

New area \(=\frac{120}{100}x \times \frac{120}{100}y\)

\(= \frac{36}{25}\text{xy } m^2\)

The difference between the Original area  and New area  is:

\(=\frac{36}{25}xy -xy\)  

\(=\frac{11}{25} xy\)

Increase %  \(= \frac{\frac{11}{25}xy}{xy} \times 100\)  

= 44%

All DiscussionsClick here to write answer

Answer :  44% Explanation: Let original length = x metres and original breadth = y metres. Original area = \(\text{xy }m^2\) Increased length  \(= \frac{120}{100}x\)  and Increased breadth \(= \frac{120}{100}y\) New area \(=\frac{120}{100}x \times \frac{120}{100}y\) \(= \frac{36}{25}\text{xy } m^2\) The difference between the Original area  and New area  is: \(=\frac{36}{25}xy -xy\)   \(=\frac{11}{25} xy\) Increase %  \(= \frac{\frac{11}{25}xy}{xy} \times 100\)   = 44% Nithin K ? answered Dec 4 '2016 at 14:38 All Comments

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