The percentage increase in the area of a rectangle, if each

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RRB TA Exam (Chennai) 2008 click here to view all questions

The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is

A40%

B42%

C44%

D46%

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Answer :  44% Explanation: Let original length = x metres and original breadth = y metres. Original area = $\text{xy }m^2$ Increased length  $= \frac{120}{100}x$  and Increased breadth $= \frac{120}{100}y$ New area $=\frac{120}{100}x \times \frac{120}{100}y$ $= \frac{36}{25}\text{xy } m^2$ The difference between the Original area  and New area  is: $=\frac{36}{25}xy -xy$   $=\frac{11}{25} xy$ Increase %  $= \frac{\frac{11}{25}xy}{xy} \times 100$   = 44% Nithin K ? answered Dec 4 '2016 at 14:38 All Comments

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