when arranged in descending order is

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RRB TA Exam (Malda) 2008 click here to view all questions

The fractions $$\frac{7}{11},\frac{16}{20},\frac{21}{22}$$ when arranged in descending order is

A$$\frac{7}{11},\frac{16}{20},\frac{21}{22}$$

B$$\frac{21}{22},\frac{7}{11},\frac{16}{20}$$

C$$\frac{21}{22},\frac{16}{20},\frac{7}{11}$$

D$$\frac{7}{11},\frac{21}{22},\frac{16}{20}$$

pavan ? Jul 2 '2017 at 12:56

Answer is \(\frac{21}{22}>\frac{16}{20}>\frac{7}{11}\)

Explanation:

\(\frac{7}{11} vs \frac{16}{20} => \frac{140 \text{ vs }176}{11 \times 20}=> \frac{7}{11}<\frac{16}{20} \)

further

\(\frac{16}{20}vs\frac{21}{22} => \frac{352 \text{ vs } 420}{20 \times 22}=>\frac{16}{20}<\frac{21}{22}\)

\(=>\) Descending order is 

\(\frac{21}{22}>\frac{16}{20}>\frac{7}{11}\)

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Answer is \(\frac{21}{22}>\frac{16}{20}>\frac{7}{11}\) Explanation: \(\frac{7}{11} vs \frac{16}{20} => \frac{140 \text{ vs }176}{11 \times 20}=> \frac{7}{11}<\frac{16}{20} \) further \(\frac{16}{20}vs\frac{21}{22} => \frac{352 \text{ vs } 420}{20 \times 22}=>\frac{16}{20}<\frac{21}{22}\) \(=>\) Descending order is  \(\frac{21}{22}>\frac{16}{20}>\frac{7}{11}\) pavan ? answered Jul 2 '2017 at 12:56 All Comments

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