64329 is divided by a certain number. While dividing the num

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RRB ASM Exam (Ajmer) 2007 click here to view all questions

64329 is divided by a certain number. While dividing the numbers 175, 114 and 213 appear as three successive remainders. The divisor is-

A184

B224

C234

D296

Nithin K ? Nov 20 '2016 at 19:24

Answer is : 234

Explanation:

There are 3 remainders and they are 3 digit numbers so it is evident that the divisor is also 3 digit number.
We have three remainders, means the number comprising of the first digits i.e. 643 was divided first and we got 175 as the remainder.
Now according to DIVIDEND = DIVISOR x QUOTIENT + REMAINDER
=> DIVISOR x QUOTIENT = DIVIDEND – REMAINDER
=> DIVISOR x QUOTIENT = 643 – 175 = 468

Now Take The Options One by one
468 is not divisible by 184
468 is not divisible by 224
468 is not divisible by 296
We see that 468 is divisible by 234 only among all the answer options; so 234 is the divisor we need.

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Answer is : 234 Explanation: There are 3 remainders and they are 3 digit numbers so it is evident that the divisor is also 3 digit number. We have three remainders, means the number comprising of the first digits i.e. 643 was divided first and we got 175 as the remainder. Now according to DIVIDEND = DIVISOR x QUOTIENT + REMAINDER => DIVISOR x QUOTIENT = DIVIDEND – REMAINDER => DIVISOR x QUOTIENT = 643 – 175 = 468 Now Take The Options One by one 468 is not divisible by 184 468 is not divisible by 224 468 is not divisible by 296 We see that 468 is divisible by 234 only among all the answer options; so 234 is the divisor we need. Nithin K ? answered Nov 20 '2016 at 19:24 All Comments

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