A man lends Rs. 1,200 for 3 years. A part he lends on 4% an

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RRB TC CC Exam (Patna) 2006 click here to view all questions

A man lends Rs. 1,200 for 3 years. A part he lends on 4% and rest on 6% and receives Rs. 192 as interest. The money he lent on 6% rate is

ARs. 720

BRs. 840

CRs. 800

DRs. 515

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Answer is : Rs. 800 If amount lend at 4% interest=x  SI = (P * T * R) / 100 Where P = x , T(Time) = 3yr , R (rate) = 4%  SI = $(x * 3 * 4)\over100$ SI = $12x\over100$ ......................(i) and at 6% interest=1200-x $SI = \frac{(P * T * R) }{100}$ Where P = (1200-x) , T(Time) = 3yr , R (rate) = 6%  $SI = \frac{(1200-x) * 3 * 6}{100}$ $SI = \frac{(1200-x) * 18}{100}$ $SI = \frac{(21600 - 18x)}{100}$ ..................(ii) Total interest is = 192  equation (i) + (ii) =192 $(12x)\over100$+ $(21600-18x)\over100$ = 192 $\frac{(12x + 21600 - 18x)}{100} = 192$ 12x + 21600 -18x = 19200 21600 - 6x =19200 6x = 21600 - 19200 6x = 2400 x=400 Finally, The money he lent on 6% rate is = 1200-x =1200 - 400 =800 Akilesh Kharvi ? answered Nov 5 '2016 at 0:29 All Comments

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