The ratio of the radii of two cylinders is 2 : 3 and the

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RRB TC CC Exam (Bangalore) 2007 click here to view all questions

The ratio of the radii of two cylinders is 2 : 3 and the ratio of their heights is 5 : 3. The ratio of their volumes will be-

A9 : 4

B4 : 9

C20 : 27

D27 : 20

Nithin K ? Nov 26 '2016 at 19:37

Answer is : 48 years

Explanation:

Let Mukesh's age = 2x   or Suresh's age =3x

After 12 years,

\(\frac{2x+12}{3x+12} = \frac{11}{15}\)

\((2x+12) \times 15 = (3x+12) \times 11\)

\(30x +180 =33x +132\)

48 = 3x

x = 16

\(\therefore \text{ The present age of Suresh will be : }3x\)

\(= 3 \times 16\)

\(= 48 \text{ yr}\)

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Answer is : 20 : 27 Explanation: Let redii be 2r and 3r respectively and height be 5h and 3h respectively \(\text{Volume ratio = } \frac{\pi \times (2r)^2 \times 5h}{\pi \times (3r)^2 \times 3h}\) \(= \frac{4 \times 5h}{9 \times 3h}\) \(= \frac{20}{27}\) Nithin K ? answered Nov 26 '2016 at 19:30 All Comments

Answer is : 48 years Explanation: Let Mukesh's age = 2x   or Suresh's age =3x After 12 years, \(\frac{2x+12}{3x+12} = \frac{11}{15}\) \((2x+12) \times 15 = (3x+12) \times 11\) \(30x +180 =33x +132\) 48 = 3x x = 16 \(\therefore \text{ The present age of Suresh will be : }3x\) \(= 3 \times 16\) \(= 48 \text{ yr}\) Nithin K ? answered Nov 26 '2016 at 19:37 All Comments

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