A box contains coins (equal number of every one) of rupee and half rupee, coins of 25 paise, 10 paise 5 paise value, 2 paise value and one paise value. The total value of coins in the box is Rs. .1158. Find the number of coins of each value.

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RRB ASM Exam (Bhubaneshwar) 2009 click here to view all questions

A box contains coins (equal number of every one) of rupee and half rupee, coins of 25 paise, 10 paise 5 paise value, 2 paise value and one paise value. The total value of coins in the box is Rs. .1158. Find the number of coins of each value.

A500

B400

C700

D600

task bot ? Jan 8 '2019 at 21:49

Answer is: [D] 600

Explanation:

Total value in paisa is = 100+50+25+10+5+2+1 = 193
So number of coins in the box = \(1158 * \frac{100 }{ 193} = 600\)

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Answer is: [D] 600 Explanation: Total value in paisa is = 100+50+25+10+5+2+1 = 193 So number of coins in the box = \(1158 * \frac{100 }{ 193} = 600\) task bot ? answered Jan 8 '2019 at 21:49 All Comments

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