A student multiplying a number by \frac{3}{5} instead of\frac{5}{3}, what is percentage error in 5 3the calculation?

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RRB GG Exam (Bhopal) 2009 click here to view all questions

A student multiplying a number by $\frac{3}{5}$ instead of $\frac{5}{3}$, what is percentage error in the calculation?

A0.44

B0.34

C0.54

D0.64

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Correct answer is: 0.64 Explanation: Let the number be x. Then, ideally he should have multiplied by  x by $\frac{5}{3}$. Hence Correct result was $x \times \frac{5}{3}= \frac{5x}{3}$.  By mistake he multiplied x by $\frac{3}{5}$ . Hence the result with error  = $\frac{3x}{5}$ Then, error = $\big(\frac{5x}{3} - \frac{3x}{5}\big) = \frac{16x}{15}$ $\text{Error}   = \big(\frac{\text{error}}{\text{True vaue}}\big)$ = $\frac{\frac{16}{15} \times x}{ \frac{5}{3} \times x}$ = 0.64 suraj ? answered Dec 17 '2019 at 21:37 All Comments

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