12 men can complete a piece of work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only women were to complete the remaining piece of work in 4 days, how many women would be required ?
12 men can complete a piece of work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only women were to complete the remaining piece of work in 4 days, how many women would be required ?
A70
B28
C66
D40
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Answer is : 70
Explanation:
12 men can complete the work in 36 days.
12 × 36 men can complete the work in 1day.
Again, 18 women can complete the work in 60 days.
18 × 60 women can complete the work in1 day.
12 × 36 men = 18 × 60 women
2 men = 5 women
Now, 8 men + 20 women
= (4 × 5 + 20) women = 40 women
18 women complete the work in 60 days.
40 womens’ 20 days’ work
=40×2018×60=2027
∴ Remaining work = 1−2027=727
∴18×60 women do 1 work in 1 day.
∴ 1 woman does =180×60 Work in 1 day
∴ 1 woman does in 4 days
=4180×60=118×15 work
∴118×15 work is done in 4 days by 1 woman
∴727 work is done in 4 days by = 18×15×727
= 70 days
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