6 men can complete a piece work in 12 days. 8 women can complete the same piece of work in 18 days where as 18 children can complete the piece of work in 10 days. 4men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day howmany men would be required totally ?
6 men can complete a piece work in 12 days. 8 women can complete the same piece of work in 18 days where as 18 children can complete the piece of work in 10 days. 4men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day howmany men would be required totally ?
A 36
B24
C18
DCannot be determined
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Answer is : 36
Explanation:
72 men = 144 women = 180 children
2 men = 4 women = 5 children
4 men +12 women + 20 children = 4 men+ 6 men+ 8 men = 18 men
When 6 men do 1 work in 12 days18 men will do the same in 4 days.
In 2 days half work will done.
Remaining work = \(\frac{1}{2}\)
\(\therefore \frac{M_1 D_1}{W_1} = \frac{M_2 D_2}{W_2}\)
=> \(\frac{1}{2}\times 6 × 12 = l \times M_2\)
=> \(M_2 = 36 = \) Number of men
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