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Wednesday, January 22, 2020

In a paged memory, the page hit ratio is 0-65. Time required

In a paged memory, the page hit ratio is 0-65. Time required to access a page from secondary memory is 100 ns and from the main memory is 10 ns. The average time required to access a page is
A78.5 ns
B68.5 ns
C68.0 ns
D41.5 ns

Answer : 41.5 ns

Explanation:

Time to access page in primary = 0.35*10 =3.5ns.
Miss ratio = (1-0.35) = 0.65
Missed pages will in secondary memory.
Time to access page in secondary memory =Miss ratio*time for secondary memory
\(=(1-0.35)\times100=65.0ns\)
Average time req is= Ts+Tp =65.0ns+3.5ns=68.5ns

Nithin K
answered Dec 7 '2016 at 22:22

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