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Sunday, January 26, 2020

The sum of the age of a father and his son is 45 years. Five years ago, the product of their ages was four times the age of the father at that time. What is the present age of the father and son?

The sum of the age of a father and his son is 45 years. Five years ago, the product of their ages was four times the age of the father at that time. What is the present age of the father and son?
A9, 36
B11, 34
C4, 41
D6, 39

Let's denote the present age of the father as $F$ and the present age of the son as $S$. According to the given information: 1. The sum of the age of the father and his son is 45 years: F+S=45 2. Five years ago, the product of their ages was four times the age of the father at that time. This can be expressed as: (F5)(S5)=4(F5) Now, let's solve this system of equations. From equation 1, we can express the present age of the father in terms of the son's age: F=45S Substitute this expression for $F$ in equation 2: (45S5)(S5)=4(45S5) =(40S)(S5)=4(40S) Expanding both sides: 40S5S200+5S=1604S 35S200=1604S 35S+4S=160+200 39S=360 S=36039 S=9.23 Now that we have the age of the son, we can find the age of the father using the equation: F=45S F=459.23 F35.77 Since ages are typically considered in whole numbers, we round the ages: The present age of the son is approximately 9 years, and the present age of the father is approximately 36 years.

rahul
answered Jan 26 '2020 at 10:24

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