Two men alone or three women alone can complete a piece of work in 4 days. In how many days can 1 woman and one man together complete the same piece of work ?
Two men alone or three women alone can complete a piece of work in 4 days. In how many days can 1 woman and one man together complete the same piece of work ?
A6 days
B $$\frac{24}{5} \text { days}$$
C$$\frac{12}{1.75}\text{ days}$$
DCannot be determined
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Answer is \(\frac{24}{5} \text { days}\)
Explanation:
2 men = 3 women
1 man + 1 woman
= \(\Big(\frac{3}{2}+1\Big)\) women = \(\frac{5}{2}\) women
\(\therefore M_1D_l = M_2D_2\)
=> \(3 \times 4 = \frac{5}{2}\times D_2\)
=> \(D_2 =\frac{3\times4\times2}{5}= \frac{24}{5}\) days
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