A sum of money is divided among A, B, C and D in the ratio of 3 : 5 : 9 : 13 respectively. If the share of C is Rs.2412 more than the share of A, then what is the total amount of money of B and D together?

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BANK PO Exam (SBI) 2008 click here to view all questions

A sum of money is divided among A, B, C and D in the ratio of 3 : 5 : 9 : 13 respectively. If the share of C is Rs.2412 more than the share of A, then what is the total amount of money of B and D together?

ARs.4,422

BRs.7,236

CRs.6,030

DRs.4,824

Nithin ? undefined

Correct answer is: Rs.7,236

Explanation:

Let the original sum be Rs. x.
Sum of the Ratios = 3 + 5 + 9 + 13 = 30

Therefore, C's share = \(\frac{9x}{30}=\frac{3x}{10}\)

A's Share = \(\frac{3x}{30}=\frac{x}{10}\)

According to the question,

\(= \frac{3x}{10} - \frac{x}{10} = 2412\)

\(x = 2412 \times 5 = \text{ Rs. 12060}\)

Thererfore, Amount received by B and D together
\(= \frac{ \left(5+13\right) }{30} \times 12060\)

= Rs.7236

All DiscussionsClick here to write answer

Correct answer is: Rs.7,236 Explanation: Let the original sum be Rs. x. Sum of the Ratios = 3 + 5 + 9 + 13 = 30 Therefore, C's share = \(\frac{9x}{30}=\frac{3x}{10}\) A's Share = \(\frac{3x}{30}=\frac{x}{10}\) According to the question, \(= \frac{3x}{10} - \frac{x}{10} = 2412\) \(x = 2412 \times 5 = \text{ Rs. 12060}\) Thererfore, Amount received by B and D together \(= \frac{ \left(5+13\right) }{30} \times 12060\) = Rs.7236 Nithin ? answered undefined All Comments

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