A sum of money is divided among A, B, C and D in the ratio of 3 : 5 : 9 : 13 respectively. If the share of C is Rs.2412 more than the share of A, then what is the total amount of money of B and D together?

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BANK PO Exam (SBI) 2008 click here to view all questions

A sum of money is divided among A, B, C and D in the ratio of 3 : 5 : 9 : 13 respectively. If the share of C is Rs.2412 more than the share of A, then what is the total amount of money of B and D together?

ARs.4,422

BRs.7,236

CRs.6,030

DRs.4,824

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Correct answer is: Rs.7,236 Explanation: Let the original sum be Rs. x. Sum of the Ratios = 3 + 5 + 9 + 13 = 30 Therefore, C's share = $\frac{9x}{30}=\frac{3x}{10}$ A's Share = $\frac{3x}{30}=\frac{x}{10}$ According to the question, $=\frac{3x}{10}-\frac{x}{10}=2412$ $x=2412\times 5=\text{ Rs. 12060}$ Thererfore, Amount received by B and D together $=\frac{(5+13)}{30}\times 12060$ = Rs.7236 Nithin ? answered undefined All Comments

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