The ratio of the age of a father and son is 17 : 7 respectively. 6 years ago the ratio of their age was 3 : 1 respectively. What is the father's present age?
The ratio of the age of a father and son is 17 : 7 respectively. 6 years ago the ratio of their age was 3 : 1 respectively. What is the father's present age?
A64 yrs
B51 yrs
C48 yrs
DCannot be determined
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Correct answer is: 51 yrs
Explanation:
Let the present age of father and son be 17x years and 7x years respectively.
According to the question,
\(\Large \frac{17x-6}{7x-6}=\frac{3}{1}\)
\(\implies 21x - 18 = 17x - 6\)
\(\implies 21x - 17x = 18 - 6\)\(\implies 4x = 12\)
\(=> x = \frac{12}{4} = 3\)
\(\text{Therefore, Father's present age} = 17×3 = 51 \text{ years}\)
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