The sum of three numbers is 136. If the ratio between first and second be 2 : 3 and that between second and third be 5 : 3, then the second number is:

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INSURANCE EXAMS (LIC) 2009 click here to view all questions

The sum of three numbers is 136. If the ratio between first and second be 2 : 3 and that between second and third be 5 : 3, then the second number is:

A40

B48

C52

D60

Nithin ? undefined

Correct answer is: 60
Explanation:

Let the three numbers be a, b and c respectively.
Now.
a : b = 2 : 3
b : c = 5 : 3

Therefore, a : b : c =  \(\Large 2 \times 5:3 \times 5:3 \times 3\)

= 10 : 15 : 9
According to the question,
a + b + c = 136
=> 10x + 15x + 9x = 136

\(\implies 34x = 136 \implies x = \frac{136}{34}=4\)
\(\therefore b = 15x = 15×4 = 60\)

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Correct answer is: 60 Explanation: Let the three numbers be a, b and c respectively. Now. a : b = 2 : 3 b : c = 5 : 3 Therefore, a : b : c =  \(\Large 2 \times 5:3 \times 5:3 \times 3\) = 10 : 15 : 9 According to the question, a + b + c = 136 => 10x + 15x + 9x = 136 \(\implies 34x = 136 \implies x = \frac{136}{34}=4\) \(\therefore b = 15x = 15×4 = 60\) Nithin ? answered undefined All Comments

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