A can complete a task in 16 days and B is 4 times faster than A. Find the part of work done by both A and B together in 1 day.

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RRB NTPC Exam 27 Jan 2021 click here to view all questions

A can complete a task in 16 days and B is 4 times faster than A. Find the part of work done by both A and B together in 1 day.

A$$\frac{5}{8}$$

B$$\frac{3}{16}$$

C$$\frac{5}{16}$$

D$$\frac{3}{20}$$

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correct answer is: option c) $\frac{5}{16}$ Explanation: First, find B's work rate. Since B is 4 times faster than A, B takes 1/4 the time A takes to complete the work. Therefore B can complete the work in 16/4 = 4 days. A's work rate is $\frac{1}{16}$ per day, and B's work rate is $\frac{1}{4}$ per day. Together, their work rate is $\frac{1}{16} + \frac{1}{4} = \frac{1}{16} + \frac{4}{16} = \frac{5}{16}$. Option a: $\frac{5}{8}$ is incorrect. This value is much higher than what A and B can do together in a day. Option b: $\frac{3}{16}$ is incorrect. This is not the correct sum of the individual work rates. Option c: $\frac{5}{16}$ is correct. This is the sum of A's and B's work rate per day. Option d: $\frac{3}{20}$ is incorrect. This value is obtained by the wrong calculation. Akhilesh ? answered Mar 30 '25 at 22:15

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