March 28, 2025 |
| | correct answer is: option c [5 litres]
Explanation: Initially, the mixture has 65 litres with a water to milk ratio of 5:8. First, determine the initial quantities of water and milk.
Let the initial quantity of water be \(5x\) litres and the initial quantity of milk be \(8x\) litres. Therefore, \(5x + 8x = 65\).
This simplifies to \(13x = 65\), so \(x = 5\).
Initial quantity of water = \(5 \times 5 = 25\) litres.
Initial quantity of milk = \(8 \times 5 = 40\) litres.
Let the quantity of water to be added be \(y\) litres. The new quantity of water becomes \(25 + y\) litres, while the quantity of milk remains 40 litres.
The new ratio of water to milk is 3:4. Thus, \(\frac{25 + y}{40} = \frac{3}{4}\).
Cross-multiplying gives \(4(25 + y) = 3 \times 40\), which simplifies to \(100 + 4y = 120\).
Therefore, \(4y = 20\), and \(y = 5\).
So, 5 litres of water must be added
Akhilesh ? answered Apr 1 '25 at 20:29 |