If M = 14, CAT = 57 then GLASS = ?

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RRB NTPC Exam 19 Jan 2021 click here to view all questions

If M = 14, CAT = 57 then GLASS = ?

A73

B51

C56

D77

Akhilesh ? Apr 18 '25 at 11:53

Correct Answer: \(\boxed{77}\)

Explanation:

The problem involves determining the numerical value of the word "GLASS" based on a specific letter-to-number encoding pattern. Here's how the solution is derived:

Steps:

1. Understand the encoding pattern using the given examples:
   - \( M = 14 \)
   - \( CAT = 57 \)

   The pattern is determined by reversing the alphabet (A=26, B=25, ..., Z=1). Each letter's value is its position from the end of the alphabet.

2. Verify the pattern with the given examples:

   
   - \( C = 24 \), \( A = 26 \), \( T = 7 \)
   - \( C + A + T = 24 + 26 + 7 = 57 \)
   - \( M = 14 \) (since M is the 14th letter from the end)

    

3. Apply the pattern to calculate "GLASS":

   
   - \( G = 20 \)
   - \( L = 15 \)
   - \( A = 26 \)
   - \( S = 8 \)
   - \( S = 8 \)
   - \( G + L + A + S + S = 20 + 15 + 26 + 8 + 8 = 77 \)

    

Final Answer: \(\boxed{77}\)

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Correct Answer: \(\boxed{77}\) Explanation: The problem involves determining the numerical value of the word "GLASS" based on a specific letter-to-number encoding pattern. Here's how the solution is derived: Steps: Understand the encoding pattern using the given examples: - \( M = 14 \) - \( CAT = 57 \) The pattern is determined by reversing the alphabet (A=26, B=25, ..., Z=1). Each letter's value is its position from the end of the alphabet. Verify the pattern with the given examples: - \( C = 24 \), \( A = 26 \), \( T = 7 \) - \( C + A + T = 24 + 26 + 7 = 57 \) - \( M = 14 \) (since M is the 14th letter from the end)   Apply the pattern to calculate "GLASS": - \( G = 20 \) - \( L = 15 \) - \( A = 26 \) - \( S = 8 \) - \( S = 8 \) - \( G + L + A + S + S = 20 + 15 + 26 + 8 + 8 = 77 \)   Final Answer: \(\boxed{77}\) Akhilesh ? answered Apr 18 '25 at 11:53

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