If sinA = 1/2 and cosB = 1/2 then find the value of A + B.

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RRB NTPC Exam 19 Jan 2021 click here to view all questions

If sinA = 1/2 and cosB = 1/2 then find the value of A + B.

A75°

B60°

C120°

D90°

Akhilesh ? Apr 17 '25 at 22:17

correct answer is: option d (90°)
Explanation:
Given: \(\sin A = \frac{1}{2}\) and \(\cos B = \frac{1}{2}\) Find \(A + B\)

\[ \sin A = \frac{1}{2} \implies A = 30^\circ \quad (\text{since } \sin 30^\circ = \frac{1}{2}) \]

\[ \cos B = \frac{1}{2} \implies B = 60^\circ \quad (\text{since } \cos 60^\circ = \frac{1}{2}) \]

\[ A + B = 30^\circ + 60^\circ = 90^\circ \]

Final Answer: \(\boxed{90^\circ}\)

All DiscussionsClick here to write answer

correct answer is: option d (90°) Explanation: Given: \(\sin A = \frac{1}{2}\) and \(\cos B = \frac{1}{2}\) Find \(A + B\) \[ \sin A = \frac{1}{2} \implies A = 30^\circ \quad (\text{since } \sin 30^\circ = \frac{1}{2}) \] \[ \cos B = \frac{1}{2} \implies B = 60^\circ \quad (\text{since } \cos 60^\circ = \frac{1}{2}) \] \[ A + B = 30^\circ + 60^\circ = 90^\circ \] Final Answer: \(\boxed{90^\circ}\) Akhilesh ? answered Apr 17 '25 at 22:17

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