The diagonal of a rhombus is 8 m and 6 m respectively. Find its area.

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RRB Non Technical Exam (Secunderabad) 2016 click here to view all questions

The diagonal of a rhombus is 8 m and 6 m respectively. Find its area.

A48 sq.m

B24 sq.m.

C12 sq.m.

D96 sq.m.

rahul ? Jan 12 '2020 at 9:51

Correct anwer is: 24 sq.m.

Explanaton:

We know that,

Area of a rhombus with diagonals d1 and d2 = $\frac{d1\times d2}{2}$

⇒ Area of rhombus = $\frac{8× 6}{2} = \frac{48}{2} = 24 \text{ sq. m.}$

∴ Area of rhombus = 24 sq. m.

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The perimeter of a triangle is 28 cm. If the length is 5/2 times its breadth, find the length and breadth of the triangle.

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RRB Non Technical Exam (Secunderabad) 2016 click here to view all questions

The perimeter of a Rectangle is 28 cm. If the length is 5/2 times its breadth, find the length and breadth of the rectangle.

A9 & 5

B10 & 4

C6 & 7

D11 & 3

rahul ? Jan 14 '2020 at 10:50

Correct Answer is: 10 & 4

Explanation:

Sides 5x and 2x

Perimeter of rectangle = 2 ( Length + Breadth)

Perimeter = 2(5x+2x) =28

x=2

Sides =10 and 4

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The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is-

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RRB ASSISTANT LOCO PILOT (Patna) 2013 click here to view all questions

The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is-

A29.46 km/ hr

B31.68 km/ hr

C36.25 km/ hr

D32.72 km/ hr

raju ? Jan 8 '2020 at 10:50

Correct answer is : 31.68 km/hr

Explanation:

Circumference = 2πr
$= 2 \times \frac{22}{7} \times \text{70 cm}$
= 440 cm

Distance travelled in 10 revolutions = 440 x 10 cm
= 4400 cm
= 44 m

$\therefore Speed = \frac{distance}{time}$

$= \frac{44}{5} \text{ m/sec}$

$= \frac{44}{5} \times \frac{18}{5} \text{ km/hr}$

$= 31.68 \text{ km/hr}$

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The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area ?

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RRB ASSISTANT LOCO PILOT (Patna) 2013 click here to view all questions

The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area ?

A37(1 / 2)%

B0.6

C0.75

DNone

rahul ? Jan 15 '2020 at 9:30

Correct answer is: $37 \frac{1}{2} \%$

Explanation:

Let original length = x and
original breadth = y.
Then, original area = xy

New length =$\frac{160x}{100} = \frac{8x}{5}$.
Let new breadth = zThen. $\frac{8x}{5} \times z = xy => z = \frac{5y}{8}$
\therefore Decrease in breadth = $\Big(\frac{3y}{8} \times \frac{1}{y} \times 100 \Big) \% = 37\frac{1}{2}\%$

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If the sides of a triangle are 5 cm, 4 cm and ??41 cm, then the area then he take

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RRB ASSISTANT LOCO PILOT (Allahabad) 2010 click here to view all questions

If the sides of a triangle are 5 cm, 4 cm and $\sqrt{41}$ cm, then the area then he take the area of triangle is

A20 $cm^2$

B$(5+4+\sqrt{41}) cm^2$

C$\frac{(5+4+\sqrt{41})}{3} cm^2$

D$10 cm^2$

No answer description available for this question. Let us discuss.

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