The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area ?

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RRB ASSISTANT LOCO PILOT (Patna) 2013 click here to view all questions

The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area ?

A37(1 / 2)%

B0.6

C0.75

DNone

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Correct answer is: $37\frac{1}{2}\mathrm{\%}$ Explanation: Let original length = x and original breadth = y. Then, original area = xy New length =$\frac{160x}{100}=\frac{8x}{5}$. Let new breadth = zThen. $\frac{8x}{5}\times z=xy=>z=\frac{5y}{8}$ \therefore Decrease in breadth = $(\frac{3y}{8}\times \frac{1}{y}\times 100)\mathrm{\%}=37\frac{1}{2}\mathrm{\%}$ rahul ? answered Jan 15 '2020 at 9:30 All Comments

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