Manoj sold an article for Rs.15,000. Had he offered a discount of 10% on the selling price he would have earned a profit of 8%. What is the cost price?

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Manoj sold an article for Rs.15,000. Had he offered a discount of 10% on the selling price he would have earned a profit of 8%. What is the cost price?

ARs.12,500

BRs.13,500

CRs.12,250

DRs.13,250

Nithin ? undefined

Correct answer is: Rs.12,500

Explanation:

Let the cost price x.
Therefore, 90% of 15000 = 108% of x 

\(= \frac{90 \times 15000}{108}\)

=> x = Rs.12500

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The present ages of Amit and his father are in the ratio of 2 : 5 respectively. Four years hence the ratio of their ages will become 5 : 11 respectively. What was the father's age five years ago?

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The present ages of Amit and his father are in the ratio of 2 : 5 respectively. Four years hence the ratio of their ages will become 5 : 11 respectively. What was the father's age five years ago?

A 40 yr

B45 yr

C30 yr

D35 yr

Nithin ? Aug 14 '2022 at 21:1

Correct answer is: 35 yr

Explanation:

Suppose the present age of Amit and his father is 2x and 5x respectively.
After 4 years the ratio of their ages,

(2x+4):(5x+4)= 5:11
\(25x + 20 = 22x+44\)

\(25x-22x=44-20\)

\(3x=24\)

\(x=8\)

Age of his father before 5 years

\(=5x-5\)

\(=5 \times 8 -5\)

\(= 40 - 5\)

= 35 yr

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B and C together can complete a work in 8 days, A and B together can complete the same work in 12 days and A and C together can complete the same work in 16 days. In how many days can A, B and C together complete the same work ?

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B and C together can complete a work in 8 days, A and B together can complete the same work in 12 days and A and C together can complete the same work in 16 days. In how many days can A, B and C together complete the same work ?

A$$3\frac{9}{13}$$

B$$7\frac{5}{13}$$

C$$7\frac{5}{12}$$

D$$3\frac{5}{12}$$

Akilesh Kharvi ? May 29 '2017 at 14:20

Answer is : \(7\frac{5}{13} \)

Explanation:

(B+C)’s 1 day’s work = \(\frac{1}{8}\)...(i)

(A+B)’s 1 day’s work = \(\frac{1}{12}  \)...(ii)

(A+C)’s 1 day’s work = \(\frac{1}{16} \)...(iii)

On adding all these three equations,

2 (A + B + C)’s 1 day’s work

\(=> \frac{1}{8}+\frac{1}{12}+\frac{1}{16} = \frac{6+4+3}{48}=\frac{13}{48}\)

=>(A + B + C)’s 1 day’s work = \(\frac{13}{96}\)

\(\therefore\) A, B and C together can complete the work in \( \frac{96}{13}= 7\frac{5}{13}\) days

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