A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

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A certain amount earns simple Interest of Rs. 1,750/- after 7 years. Had the interest been 2% more, how much more interest would it have earned ?

ARs. 35/-

BRs. 350/-

CRs. 245/-

DCannot be determined

nithin ? undefined

To find out how much more interest would have been earned if the interest rate were 2% more,
we need to calculate the interest earned at the original rate and the interest earned at the increased rate.
Let's denote: - Original interest rate = \(R\) (in percentage)
- Principal amount = \(P\)
- Time period = \(T\) (in years)
- Original interest earned = \(I_1\)
- Interest earned at the increased rate = \(I_2\)
Given: - \(I_1 = Rs. 1,750\) - \(T = 7\) years We can use the formula for simple interest: \[I = \frac{P \times R \times T}{100}\] For the original interest rate: \[1750 = \frac{P \times R \times 7}{100}\] \[P \times R = \frac{1750 \times 100}{7}\] \[P \times R = 25000\] Now, if the interest rate were increased by 2%, the new rate would be \(R + 2\) (in percentage). For the increased interest rate: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] The difference in interest would be: \[\text{Difference} = I_2 - I_1\] Let's calculate \(I_2\) and the difference: \[I_2 = \frac{P \times (R + 2) \times 7}{100}\] \[= \frac{P \times (R \times 7 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 2 \times 7)}{100}\] \[= \frac{P \times (25000 + 14)}{100}\] \[= \frac{P \times 25014}{100}\] \[= 250.14P\] Now, calculate the difference: \[\text{Difference} = I_2 - I_1\] \[= 250.14P - 1750\] We have the value of \(P\) from the earlier calculation: \[P \times R = 25000\] \[R = \frac{25000}{P}\] Substitute this value of \(R\) into the difference equation: \[\text{Difference} = 250.14P - 1750\] \[= 250.14P - 1750\] \[= 250.14 \times \frac{25000}{R} - 1750\] Now, we need to determine the value of \(R\) (original interest rate). However, it's not given, so we can't determine the exact difference. Therefore, the answer is option D: Cannot be determined.

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Deepa bought a calculator at 30% discount on the listed price. Had she not got the discount, she would have paid Rs. 82.50 extra. At what price did she buy the calculator?

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Deepa bought a calculator at 30% discount on the listed price. Had she not got the discount, she would have paid Rs. 82.50 extra. At what price did she buy the calculator?

A192.50

B275

C117.85

DCant be determined

Nithin ? undefined

Correct answer is: 192.50

Explanation:

Let the original price be x, then
30% of x = 82.50
x = \(\frac{82.50}{30} \times 100\) = Rs. 275
Deepa bought calculator in 275 – 82.50 = Rs. 192.50

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Seats for Maths, Physics and Biology are in the ratio of 5 : 7 : 8 respectively. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the respective ratio of increased seats?

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Seats for Maths, Physics and Biology are in the ratio of 5 : 7 : 8 respectively. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the respective ratio of increased seats?

A2 : 3 : 4

B6 : 7 : 8

C6 : 8 : 9

DCannot be determined

Nithin ? Aug 11 '2022 at 21:12

Correct answer is: 2 : 3 : 4

Explanation:

Let the initial seats for Maths, Physics and Biology be 5x. 7x and 8x respectively.

Now. new seats for Maths = \(\Large \frac{5x \times 140}{100}\)

For Physics = \(\Large \frac{7x \times 150}{100}\)

and for Biology = \(\Large \frac{8x \times 175}{100}\)

Therefore, Required ratio

\(\Large \frac{5x \times 140}{100} : \Large \frac{7x \times 150}{100}: \Large \frac{8x \times 175}{100}\)

\(\Large 5 \times 140:\Large 7 \times 150: \Large 8 \times 175\)

\(= 2 : 3 : 4\)

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A motor starts with the speed of 70 kmph with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms ?

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A motor starts with the speed of 70 kmph with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms ?

A$2\frac{1}{ 4}$ hours

B$4 \frac{1}{2}$ hours

C4 hours 5 minutes

DCannot be determined

ranjith ? Feb 23 '2020 at 20:40

Correct answer is: \(4 \frac{1}{2}\) hours

Explanation:

 

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