Income of two companies A and B are in the ratio of 5 : 8. Had the income of company 'A' been more by Rs.25 lakhs, the ratio of their income would have been 5 : 4 respectively. What is the income of company 'B'?

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Income of two companies A and B are in the ratio of 5 : 8. Had the income of company 'A' been more by Rs.25 lakhs, the ratio of their income would have been 5 : 4 respectively. What is the income of company 'B'?

ARs.80 lakhs

BRs.50 lakhs

CRs.40 lakhs

DRs.60 lakhs

Nithin ? undefined

Correct answer is: Rs.40 lakhs

Explanation:

A : B = 5 : 8
Let A's income be 5x and B's income be 8x.
According to question.

\(\Large \frac{5x+25}{8x}=\frac{5}{4}\)

\(\frac{5 \left(x+5\right) }{4 \times 2x}=\frac{5}{4} => \frac{x+5}{2x} = 1\)

x + 5 = 2x
x = 5

\(\text{B's Income} = 8x = 8×5\)

= Rs.40 lakhs.

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In a school the number of boys and that of the girls are in the respective ratio of 2 : 3. If the number of boys is increased by 20% and that of girls is increased by 10%, what will be the new ratio of number of boys to that of the girls?

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In a school the number of boys and that of the girls are in the respective ratio of 2 : 3. If the number of boys is increased by 20% and that of girls is increased by 10%, what will be the new ratio of number of boys to that of the girls?

A14 : 5

B5 : 8

C13 : 4

DNone of these

Nithin ? undefined

Correct answer is: None of these

Explanation:

Ratio of no. boys : girls = 2 : 3
Let the no. of boys = 2x
Then the no. of girls = 3x
No. of boys after 20% increase = 1.20 x 2x = 2.4 x.
No. of girls after 10% increase = 1.10 x 3x = 3.3x
Required ratio

\(= \frac{2.4x}{3.3x}=\frac{8}{11} = 8 : 11\)

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Mr.Shivkumar started a business investing Rs.25,000 in 1996. In 1997 he invested an additional amount of Rs.10,000 and Mr.Rakesh joined him with an amount of Rs.35,000 in 1998. Mr.Shivkumar invested another additional amount of Rs.10,000 and Mr.Suresh joined them with an amount of Rs.35,000. What will be Rakesh's share in the profit of Rs.1,50,000 earned at the end of three years from the start of the business in 1996?

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Mr.Shivkumar started a business investing Rs.25,000 in 1996. In 1997 he invested an additional amount of Rs.10,000 and Mr.Rakesh joined him with an amount of Rs.35,000 in 1998. Mr.Shivkumar invested another additional amount of Rs.10,000 and Mr.Suresh joined them with an amount of Rs.35,000. What will be Rakesh's share in the profit of Rs.1,50,000 earned at the end of three years from the start of the business in 1996?

ARs.70,000

BRs.50,000

CRs.45,000

D Rs.75,000

Nithin ? Aug 3 '2022 at 5:59

Correct answer: Rs.50,000

Explanation:

Shivkumar's equivalent capital

= (25000 x 3) + (10000 x 2) + (10000 x 1) = 105000

Rakesh's equivalent capital = 35000 x 2 = 70000

Suresh's equivalent capital = 35000 x 1 = 35000

Total profit of Rs.150000 will be distributed in the ratio of their equivalent capitals.

Shivkumar : Rakesh : Suresh = 105 : 70 : 35

= 3 : 2 : 1

Rakesh's share in the total profit = 2/(3 + 2 + 1) x 150000

= Rs.50000
 

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Mr.X a businessman had the income in the year 1995, such that he can-led a profit of 20% on his investment in the business. In the year 1996 his investment was less by Rs.5,000 but still had the same income (Income = Investment + Profit) as that in 1995. Thus the per cent profit earned in 1996 increased by 6%. What was his investment in 1995?

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Mr.X a businessman had the income in the year 1995, such that he can-led a profit of 20% on his investment in the business. In the year 1996 his investment was less by Rs.5,000 but still had the same income (Income = Investment + Profit) as that in 1995. Thus the per cent profit earned in 1996 increased by 6%. What was his investment in 1995?

ARs.1,02,000

BRs.1,52,500

CRs.1,05,000

D Data inadequate

Nithin ? Aug 2 '2022 at 21:45

Correct answer is: Rs.1,05,000

Explanation:

Let the investment in 1995 be Rs.x

Income in 1995 with 20% profit = 1.20x

Also the income in 1996 = 1.20x

Investment in 1996

= Rs.(x - 5000)

Profit in 1996 = (20 + 6)% = 26%

Income in 1996 with 26% profit

= 1.26 (x - 5000)

Therefore, 1.26 (x 5000) = 1.20x

0.06 x = 1.26 x 5000

\(x = \Large \frac{6300}{0.06}\)

x = Rs.105000

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A man starts going for morning walk every day. The distance walked by him on the first day was 2 kms. Everyday he walks half of the distance walked on the previous day. What can be the maximum total distance walked by him in his life time ?

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A man starts going for morning walk every day. The distance walked by him on the first day was 2 kms. Everyday he walks half of the distance walked on the previous day. What can be the maximum total distance walked by him in his life time ?

A4 kms.

B 120 kms.

C18 kms.

DData inadequate

akilesh kharvi ? Jun 7 '2020 at 15:14

Correct answer is: 4 kms.

Explanation:

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