The respective ratio of the present ages of a mother and daughter is 7 : 1. Four years ago the respective ratio of their ages was 19:1. What will be the mother's age four years from now ?

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The respective ratio of the present ages of a mother and daughter is 7 : 1. Four years ago the respective ratio of their ages was 19:1. What will be the mother's age four years from now ?

A42 years

B38 years

C46 years

D36 years

Nithin ? undefined

Correct answer is: 46 years

Explanation:

Let the present ages of mother and daughter be x and y respectively.

\(\frac{y}{x}=\frac{1}{7} \implies x= 7y\)

\(\frac{y-4}{x-4} = \frac{1}{19} \implies 19y - 76 = x - 4 \implies x = 19y - 72 \)

\(\implies 7y = 19y - 72 \implies y = \text{6 and x }= 42\)

Age of mother 4 years from now = 42 + 4 = 46

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4 men can complete a piece of work in 2 days. 4 women can complete the same piece of work in 4 days whereas 5 children can complete the same piece of work in 4 days. If 2 men, 4 women and 10 children work together, in how many days can the work be completed ?

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4 men can complete a piece of work in 2 days. 4 women can complete the same piece of work in 4 days whereas 5 children can complete the same piece of work in 4 days. If 2 men, 4 women and 10 children work together, in how many days can the work be completed ?

A 1 day

B3 days

C2 days

D4 days

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