The respective ratio of the present ages of a mother and daughter is 7 : 1. Four years ago the respective ratio of their ages was 19:1. What will be the mother's age four years from now ?
The respective ratio of the present ages of a mother and daughter is 7 : 1. Four years ago the respective ratio of their ages was 19:1. What will be the mother's age four years from now ?
A42 years
B38 years
C46 years
D36 years
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Correct answer is: 46 years
Explanation:
Let the present ages of mother and daughter be x and y respectively.
\(\frac{y}{x}=\frac{1}{7} \implies x= 7y\)
\(\frac{y-4}{x-4} = \frac{1}{19} \implies 19y - 76 = x - 4 \implies x = 19y - 72 \)
\(\implies 7y = 19y - 72 \implies y = \text{6 and x }= 42\)
Age of mother 4 years from now = 42 + 4 = 46
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