A train running at the speed of 20 metres/ second crosses a pole in 24 seconds less than the time it requires to cross a platform thrice its length at the same speed. What is the length of the train ?

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A train running at the speed of 20 metres/ second crosses a pole in 24 seconds less than the time it requires to cross a platform thrice its length at the same speed. What is the length of the train ?

A270 metres

B160 metres

C180 metres

DCannot be determined

ranjith ? Feb 23 '2020 at 21:8

Correct answer : 160 metres

Explanation:

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12 men can complete a piece of work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only women were to complete the remaining piece of work in 4 days, how many women would be required ?

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12 men can complete a piece of work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only women were to complete the remaining piece of work in 4 days, how many women would be required ?

A70

B28

C66

D40

Akilesh Kharvi ? May 27 '2017 at 16:15

Answer is : 70

Explanation:

12 men can complete the work in 36 days.

12 × 36 men can complete the work in 1day.

Again, 18 women can complete the work in 60 days.

18 × 60 women can complete the work in1 day.

12 × 36 men = 18 × 60 women

2 men = 5 women

Now, 8 men + 20 women

= (4 × 5 + 20) women = 40 women

18 women complete the work in 60 days.

40 womens’ 20 days’ work

\(=\frac{40\times20}{18\times60}= \frac{20}{27}\)

\(\therefore\) Remaining work = \(1 - \frac{20}{27}= \frac{7}{27}\)

\(\therefore 18 \times 60\)  women do 1 work in 1 day.

\(\therefore\) 1 woman does \(=\frac{ 1}{80 \times 60}\) Work in 1 day

\(\therefore\) 1 woman does in 4 days

\(= \frac{4}{180\times60} = \frac{1}{18\times15} \) work

 \(\therefore \frac{1}{18 \times 15}\) work is done in 4 days by 1 woman

\(\therefore \frac{7}{27}\) work is done in 4 days by = \(\frac{18\times15\times7}{27}\)

= 70 days

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