In round-robin CPU scheduling, as the time quantum increases
In round-robin CPU scheduling, as the time quantum increases, the average turn around time
In round-robin CPU scheduling, as the time quantum increases, the average turn around time
A dirty bit points to a
Akilesh Kharvi ? Dec 8 '2016 at 20:2
Answer: the page whose data is to be updated because of new computations
Explanation:
A dirty bit is a flag that indicates whether an attribute needs to be updated. Such situations usually occur when a bit in a memory cache or virtual memory page that has been changed by a processor but has not been updated in the storage. this dirty bit is point to the page whose data is to be updated because of new computations so answer is option (d ) the page whose data is to be updated because of new computations.
Which of the following page replacement policies may lead to Belady's anomaly ?
Akilesh Kharvi ? Dec 8 '2016 at 20:0
Answer: FIFO
Explanation:
Belady’s anomaly proves that it is possible to have more page faults when increasing the number of page frames while using the First in First Out (FIFO) page replacement algorithm.
Reference: https://en.wikipedia.org/wiki/B%C3%A9l%C3%A1dy%27s_anomaly
Resource allocation graphs are useful in
Akilesh Kharvi ? Dec 8 '2016 at 19:42
Answer: deadlock avoidance
Explanation:
A relational database table is often described as “normalized” if it is in the Third Normal Form because most of the 3NF tables are free of insertion, update, and deletion anomalies. so answer is deadlock avoidance
At a particular time of computation, the value of a counting semaphore is 7. Then 20 P operations and 'x' V operations were completed on this semaphore. If the final value of the semaphore is 5, x will be
Nithin K ? Dec 7 '2016 at 22:24
Answer: 18
Explanation:
P means wait ie S:= S-1;
V means signal i.e S= S+1;
Each P operation will decrease the semaphore value by 1 and V operation increases by 1.
So,
7 -> 20p -> Xv = 5
=>7-20+X=5
=> X = 18.