If x is less than y by 25%, then y exceed x by.…
If x is less than y by 25%, then y exceed x by....
If x is less than y by 25%, then y exceed x by....
rahul ? Jan 11 '2020 at 17:50
Correct answer is : \(33 \frac{1}{3} \%\)
Explanation:
Let us assume y =100, so according to question X is less than y by 25 % , so x =75,
\(\text{Hence y exceed x by =} \frac{25}{75} \times 100 = 33.33 % or 33 1/3 \text{ %}\)
A student multiplying a number by $\frac{3}{5}$ instead of $\frac{5}{3}$, what is percentage error in the calculation?
suraj ? Dec 17 '2019 at 21:37
Correct answer is: 0.64
Explanation:
Let the number be x.
Then, ideally he should have multiplied by x by \(\frac{5}{3}\). Hence Correct result was \(x \times \frac{5}{3}= \frac{5x}{3}\).
By mistake he multiplied x by \(\frac{3}{5}\) . Hence the result with error = \(\frac{3x}{5} \)
Then, error = \(\big(\frac{5x}{3} - \frac{3x}{5}\big) = \frac{16x}{15} \)
\(\text{Error} = \big(\frac{\text{error}}{\text{True vaue}}\big) \)
= \(\frac{\frac{16}{15} \times x}{ \frac{5}{3} \times x} \)
= 0.64
A man can do a piece of work in 5 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone?
raveesh ? Dec 23 '2019 at 9:17
Correct Answer is : 7.5 days
Explanation:
In this type of question, where we have one person work and together work done. Then we can easily get the other person work just by subtracting them. As,
Son's one day work
\(\begin{aligned} \left(\frac{1}{3}-\frac{1}{5} \right) \\ =\left(\frac{5-3}{15} \right) \\ = \frac{2}{15} \end{aligned}\)
So son will do whole work in \(\frac{15}{2}\) days
which is =\(\begin{aligned} 7\frac{1}{2}days \end{aligned}\)
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together, but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in
prakash ? Dec 18 '2019 at 9:8
Correct answer is: 12 days
Explanation:
The work completed by both in 2 days is
\(2\big(\frac{ 1}{15} + \frac{1}{10}\big) = \frac{1}{3}.\)
Work done by A alone is \(\frac{2}{3}\)
For full work A needs 15 days
For 2/3 work the days needed is \( (\frac{2}{3})\times15\) = 10 days.
The work was completed in 10 +2 = 12 days.
5 persons can prepare an admission list in 8 days working 7 hours a day. If 2 persons join them so as to complete the work in 4 days, they need to work per For
prashanth ? Dec 18 '2019 at 9:30
Correct answer is: 10 hours
Explanation:
\(\Large \frac{5 \text{ person} \times 8 \text{ days} \times 7hr}{1}= \frac{\left(5+2 \text{ person}\right) \times 4 \text{ days} \times Hperday}{1}\)
=10 hours