The area of the base of a rectangular tank is 6500 cm^2 and the volume of water contained in it is 2.6 cubic metres. The depth of the water tank is-

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RRB ASSISTANT LOCO PILOT (Patna) 2013 click here to view all questions

The area of the base of a rectangular tank is 6500 cm^2 and the volume of water contained in it is 2.6 cubic metres. The depth of the water tank is-

A2.5 metre

B3 metre

C5.5 metre

D4 metre

rahim ? Jan 8 '2020 at 10:32

Correct answer is: 4 metre

Explanation:

\(l \times b = 6500 \text{ cm}^2 = 0.65 \text{ m}^2\)
\(l \times b \times h = 2.6 \text{ m}^3\)
\(0.65 \times h = 2.6\)
\(h =\frac{2.6}{0.65}\)
\(h = 4m\)

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What is the volume in cubic cm of a pyramid whose area of

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RRB TC CC Exam (Mumbai) 2006 click here to view all questions

What is the volume in cubic cm of a pyramid whose area of the base is 25 sq cm and height 9 cm?

A105

B90

C60

D75

Akilesh Kharvi ? Nov 7 '2016 at 19:14

Answer is : 75

\(\text{Volume of pyramid }=\frac{1}{2} \times \text{Area of base} \times \text{height }\)

\(= \frac{1}{2} \times 25 \times 9 \)

\(= 75 cm^3\)

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What part of a ditch, 48 m long 16.5 m broad and 4 m deep can be filled

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RRB TC CC Exam (Chandigarh) 2008 click here to view all questions

What part of a ditch, 48 m long 16.5 m broad and 4 m deep can be filled by the earth got by digging a cylindrical tunnel of diameter 4 m and length 56 m ?

A$$\frac{1}{9}$$

B$$\frac{2}{9}$$

C$$\frac{7}{9}$$

D$$\frac{8}{9}$$

Nithin K ? Apr 7 '2018 at 16:54

Answer is : b.) \(\frac{2}{9}\)

Explanation:

Volume of the earth dugout as a tunnel = πr2h

= \(\Big(\frac{22}{7}\Big) \times 2 \times 2 \times 56 \)

= \(\text{704 }m^3 \)
\(\text{Volume of the ditch = }\frac{(48 \times 33)}{(2)}\times 4 \implies 24 \times 33 \times 4 \implies \text{3168 }m^3 \)
∴ \(\text{Part required = }\frac{704}{3168} \implies \frac{2}{9}\)

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The radius of a right circular cone is 3 cm and its height is 4 cm

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RRB TA Exam (Malda) 2008 click here to view all questions

The radius of a right circular cone is 3 cm and its height is 4 cm. The curved surface of the cone will be

A$$12 \pi \text{ sq.cm}$$

B$$15 \pi \text{ sq.cm } $$

C$$18 \pi \text{ sq.cm }$$

D$$ 21 \pi \text{ sq.cm} $$

balakrishna ? Jul 2 '2017 at 11:27

Answer is \(15 \pi \text{ sq.cm }\)

Explanation:

Slant height of the cone \(l = \sqrt{r^2+h^2}\)

= \(\sqrt{3^2+4^2}\)

= \(\sqrt{9+16}\)

=\(\sqrt{25}=5 \text { cm}\)

\(\therefore\) Area of the curved surface

= \(\pi rl \)

\(=\pi \times3\times5\)

\(= 15 \pi \text{ sq.cm}\)

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